Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
D.C. Circuits
The potential divider
- 3 things to know
- Component 2
Overview
Recall questions on what a potential divider is, the divider equation and its ratio form, why the supply divides in proportion to the resistances, using a variable resistor as a divider, and worked output calculations including the effect of a load.
What you need to know
Answer each one before you reveal it.
State the potential divider equation for the output taken across the second of two resistors.
What is the advantage of using large resistances in a potential divider?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is a potential divider?
Model answer
A potential divider is two or more resistors in series across a supply, arranged so that a chosen fraction of the supply potential difference is available across one of them.
- 2
State the potential divider equation for the output taken across the second of two resistors.
Model answer
The output is Vₒᵤₜ = Vᵢₙ × R₂/(R₁ + R₂), where R₂ is the resistor across which the output is taken.
- 3
Derive the potential divider equation.
Model answer
The same current I = Vᵢₙ/(R₁ + R₂) passes through both resistors, and the output is IR₂. Substituting for I gives Vₒᵤₜ = Vᵢₙ R₂/(R₁ + R₂).
- 4
A 12 V supply is applied across a 3.0 kΩ and a 9.0 kΩ resistor in series. Calculate the potential difference across the 9.0 kΩ resistor.
Model answer
The output is 12 × 9.0 ÷ 12.0 = 9.0 V. The 3.0 kΩ resistor then takes 3.0 V, and the two add to the 12 V supply.
- 5
A 15 V supply is to be divided to give 5.0 V across a 2.0 kΩ resistor. Calculate the other resistance required.
Model answer
The ratio R₂/(R₁ + R₂) must be 1/3, so R₁ + R₂ = 6.0 kΩ and R₁ = 4.0 kΩ. Substituting back, 15 × 2.0 ÷ 6.0 = 5.0 V as required.
- 6
Why do the two resistances in a potential divider matter only through their ratio when the divider is unloaded?
Model answer
The output fraction is R₂/(R₁ + R₂). That expression depends only on the ratio of the resistances and not on their individual sizes.
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