Eduqas A-Level Physics A420QS
Basic Physics
Kinematics
Dynamics
Energy Concepts
Circular Motion
Vibrations
Kinetic Theory
Thermal Physics
Conduction of Electricity
Resistance
D.C. Circuits
Capacitance
Solids Under Stress
Electrostatic and Gravitational Fields of Force
Using Radiation to Investigate Stars
Orbits and the Wider Universe
The Nature of Waves
Wave Properties
Refraction of Light
Photons
Lasers
Nuclear Decay
Particles and Nuclear Structure
Nuclear Energy
Magnetic Fields
Electromagnetic Induction
Option A: Alternating CurrentsOption A
Option B: Medical PhysicsOption B
Option C: The Physics of SportsOption C
Option D: Energy and the EnvironmentOption D
Mathematical Requirements (Appendix C)
Circular Motion
Applying the circular motion equations
- 3 things to know
- Component 1
Overview
Recall questions on what supplies the centripetal force in each case, worked force and acceleration calculations for a whirled object, a car on a bend and a satellite, the greatest speed a bend allows, and why the speed can be constant while the velocity is not.
What you need to know
Answer each one before you reveal it.
Why is a racing track banked at the corners?
Which force provides the centripetal force for a conical pendulum?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Which force provides the centripetal force for a car turning a corner on a level road?
Model answer
Friction between the tyres and the road surface, acting horizontally towards the centre of the bend, provides the centripetal force.
- 2
A level bend has radius 60.0 m and the maximum frictional force is 0.700 times the car's weight. Calculate the maximum cornering speed. Take g as 9.81 m s⁻².
Model answer
Setting mv²/r equal to 0.700mg gives v = √(0.700 × 9.81 × 60.0) = 20.3 m s⁻¹. Substituting back, 20.3²/60.0 = 6.87 m s⁻², which equals 0.700 × 9.81 m s⁻².
- 3
Why does the maximum safe cornering speed on a level road not depend on the mass of the car?
Model answer
Both the required centripetal force and the maximum available friction are proportional to the mass, so the mass cancels from the condition and only the radius and the friction coefficient matter.
- 4
Why is a racing track banked at the corners?
Model answer
Banking tilts the normal contact force so that it has a horizontal component pointing towards the centre of the bend, which supplies part or all of the centripetal force without relying on friction.
- 5
Which force provides the centripetal force for a conical pendulum?
Model answer
The horizontal component of the tension in the string provides the centripetal force, while the vertical component supports the weight of the bob.
- 6
A conical pendulum bob of mass 0.150 kg swings with the string at 30.0° to the vertical. Calculate the tension in the string. Take g as 9.81 m s⁻².
Model answer
The vertical component must support the weight, so T cos 30.0° = 0.150 × 9.81 and T = 1.70 N along the string. Multiplying 1.70 N by cos 30.0° returns 1.47 N, the weight of the bob.
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