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Circular Motion

Applying the circular motion equations

  • 3 things to know
  • Component 1

Overview

Recall questions on what supplies the centripetal force in each case, worked force and acceleration calculations for a whirled object, a car on a bend and a satellite, the greatest speed a bend allows, and why the speed can be constant while the velocity is not.

What you need to know

Answer each one before you reveal it.

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Key term

Which force provides the centripetal force for a car turning a corner on a level road?

Key term

Why is a racing track banked at the corners?

Key term

Which force provides the centripetal force for a conical pendulum?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Which force provides the centripetal force for a car turning a corner on a level road?

    Model answer

    Friction between the tyres and the road surface, acting horizontally towards the centre of the bend, provides the centripetal force.

  2. 2

    A level bend has radius 60.0 m and the maximum frictional force is 0.700 times the car's weight. Calculate the maximum cornering speed. Take g as 9.81 m s⁻².

    Model answer

    Setting mv²/r equal to 0.700mg gives v = √(0.700 × 9.81 × 60.0) = 20.3 m s⁻¹. Substituting back, 20.3²/60.0 = 6.87 m s⁻², which equals 0.700 × 9.81 m s⁻².

  3. 3

    Why does the maximum safe cornering speed on a level road not depend on the mass of the car?

    Model answer

    Both the required centripetal force and the maximum available friction are proportional to the mass, so the mass cancels from the condition and only the radius and the friction coefficient matter.

  4. 4

    Why is a racing track banked at the corners?

    Model answer

    Banking tilts the normal contact force so that it has a horizontal component pointing towards the centre of the bend, which supplies part or all of the centripetal force without relying on friction.

  5. 5

    Which force provides the centripetal force for a conical pendulum?

    Model answer

    The horizontal component of the tension in the string provides the centripetal force, while the vertical component supports the weight of the bob.

  6. 6

    A conical pendulum bob of mass 0.150 kg swings with the string at 30.0° to the vertical. Calculate the tension in the string. Take g as 9.81 m s⁻².

    Model answer

    The vertical component must support the weight, so T cos 30.0° = 0.150 × 9.81 and T = 1.70 N along the string. Multiplying 1.70 N by cos 30.0° returns 1.47 N, the weight of the bob.

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