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Acid-Base Equilibria

Proton transfer and conjugate pairs

  • 3 things to know
  • A2 Unit 3

Overview

Recall questions on acid, according to the Lowry-Bronsted model, base, according to the Lowry-Bronsted model, conjugate base of an acid and conjugate acid of a base.

What you need to know

Answer each one before you reveal it.

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Key term

Define an acid, a base and the conjugate base of an acid in the Lowry-Brønsted model.

Key term

Identify both conjugate acid-base pairs in the equilibrium CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺.

Key term

Water behaves as an acid towards ammonia but as a base towards hydrogen chloride. What is the name for this behaviour?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is an acid, according to the Lowry-Bronsted model?

    Model answer

    An acid is a proton donor: a species that gives away a hydrogen ion, H⁺, to another species.

  2. 2

    What is a base, according to the Lowry-Bronsted model?

    Model answer

    A base is a proton acceptor: a species that takes a hydrogen ion, H⁺, from another species.

  3. 3

    Why is defining an acid as a proton donor more useful than defining it as a substance that releases H⁺ in water?

    Model answer

    The proton-donor definition makes no mention of water, so it also covers proton transfers in other solvents and in the gas phase. The reaction of ammonia gas with hydrogen chloride gas to form ammonium chloride is an acid-base reaction on this model even though no solvent is present.

  4. 4

    Define the conjugate base of an acid.

    Model answer

    The conjugate base is the species that remains once the acid has donated its proton. Ethanoic acid, CH₃COOH, has the ethanoate ion, CH₃COO⁻, as its conjugate base.

  5. 5

    Define the conjugate acid of a base.

    Model answer

    The conjugate acid is the species formed when the base has accepted a proton. Ammonia, NH₃, has the ammonium ion, NH₄⁺, as its conjugate acid.

  6. 6

    Identify both conjugate acid-base pairs in the equilibrium CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺.

    Model answer

    The first pair is CH₃COOH and CH₃COO⁻, because the acid loses a proton to become the ethanoate ion. The second pair is H₂O and H₃O⁺, because water accepts that proton to become the oxonium ion. Members of a conjugate pair always differ by exactly one H⁺.

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