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Aromaticity

Benzene: shape, bonding and delocalisation

  • 3 things to know
  • A2 Unit 4

Overview

Recall questions on delocalisation, arene and phenyl group.

What you need to know

Answer each one before you reveal it.

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Process

Describe the shape of a benzene molecule.

Key term

Give the evidence from bond lengths that rules out the alternating-bond model of benzene.

Who and when

How does the existence of only one 1,2-dibromobenzene argue against alternating single and double bonds?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the shape of a benzene molecule.

    Model answer

    Benzene, C₆H₆, is a planar regular hexagon of six carbon atoms, each carrying one hydrogen atom that also lies in the plane. All the bond angles are 120 degrees and all six carbon-to-carbon bonds are the same length.

  2. 2

    Describe the bonding in benzene.

    Model answer

    Each carbon uses three of its four outer electrons to form sigma bonds, two to neighbouring carbons and one to a hydrogen atom. The fourth electron occupies a p orbital perpendicular to the ring plane, and these six p orbitals overlap sideways all the way round, so the six electrons are delocalised into rings of electron density above and below the plane of the ring.

  3. 3

    What is meant by delocalisation?

    Model answer

    Delocalisation means that electrons are not confined between one particular pair of atoms but are spread over three or more atoms. In benzene the six p electrons belong to the ring as a whole rather than to any individual carbon-to-carbon bond.

  4. 4

    Why must benzene be planar for delocalisation to occur?

    Model answer

    The p orbitals can only overlap sideways with one another if they are all parallel, and that requires every carbon and its three sigma bonds to lie in the same plane. Any buckling of the ring would reduce the overlap and destroy the continuous delocalised system.

  5. 5

    The carbon-to-carbon bond length in benzene is 0.139 nm. Compare this with the values in ethane and ethene, and explain what it shows.

    Model answer

    A carbon-to-carbon single bond is about 0.154 nm and a double bond about 0.134 nm, so the benzene value lies between the two. Every bond in the ring is intermediate in length and identical to the others, which shows that the ring contains neither alternating single and double bonds nor six of one kind, but six identical bonds of intermediate character.

  6. 6

    What did the Kekulé model propose for benzene, and what does it predict about bond lengths?

    Model answer

    It proposed a six-membered ring with alternating single and double carbon-to-carbon bonds. That model predicts two different bond lengths within the ring, about 0.154 nm and about 0.134 nm alternating, so the ring would not be a regular hexagon.

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