WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Acid-Base Equilibria
Water, Kw and the pH scale
- 3 things to know
- A2 Unit 3
Overview
Recall questions on Water and the pH scale.
What you need to know
Answer each one before you reveal it.
State the units of Kw.
At 310 K, Kw = 2.4 × 10⁻¹⁴ mol² dm⁻⁶. Calculate the pH of pure water at body temperature.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write the equation for the ionisation of water and explain why it happens at all.
Model answer
H₂O(l) ⇌ H⁺(aq) + OH⁻(aq), or written as a proton transfer between two molecules, 2H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq). Water is very slightly amphoteric, so one molecule can pass a proton to another, although at any moment only about one molecule in 5.6 × 10⁸ has done so.
- 2
Write the expression for the ionic product of water and state its value at 298 K.
Model answer
Kw = [H⁺][OH⁻], and at 298 K its value is 1.00 × 10⁻¹⁴ mol² dm⁻⁶.
- 3
Why does [H₂O] not appear in the expression for Kw?
Model answer
Only a minute fraction of the water ionises, so the concentration of undissociated water stays effectively constant at about 55.5 mol dm⁻³. That constant is combined with the equilibrium constant to give the simpler quantity Kw.
- 4
State the units of Kw.
Model answer
The units are mol² dm⁻⁶, because Kw is the product of two concentrations each measured in mol dm⁻³.
- 5
How is pH defined?
Model answer
pH = −log₁₀[H⁺], where [H⁺] is the hydrogen ion concentration in mol dm⁻³. To go the other way, [H⁺] = 10⁻ᵖᴴ.
- 6
Show that pH + pOH = 14.00 at 298 K.
Model answer
Since [H⁺][OH⁻] = 1.00 × 10⁻¹⁴, taking negative logarithms of both sides gives −log[H⁺] − log[OH⁻] = −log(1.00 × 10⁻¹⁴). That is pH + pOH = 14.00, so pKw = 14.00 at this temperature.
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