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Chemistry of the D-Block Transition Metals

Ligand exchange and changes in coordination number

  • 3 things to know
  • A2 Unit 3

Overview

Recall questions on ligand exchange.

What you need to know

Answer each one before you reveal it.

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Key term

Why does the coordination number fall from six to four when chloride ions replace water ligands on a copper(II) ion?

Numbers

Concentrated hydrochloric acid is added to a pink solution of cobalt(II) chloride. Write the equation and state the colour change.

Key term

Cobalt chloride paper is used to test for water. Describe the colour change and explain it.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is meant by ligand exchange?

    Model answer

    It is a reaction in which one ligand in a complex ion is replaced by another. The new ligand donates a lone pair to the metal in place of the old one, and the oxidation state of the metal is unchanged.

  2. 2

    Concentrated hydrochloric acid is added to a pale blue solution of copper(II) sulfate. Write the equation and describe what is seen.

    Model answer

    [Cu(H₂O)₆]²⁺(aq) + 4Cl⁻(aq) ⇌ [CuCl₄]²⁻(aq) + 6H₂O(l). The pale blue solution turns yellow, usually passing through green as the mixture contains both ions at once.

  3. 3

    Why does the coordination number fall from six to four when chloride ions replace water ligands on a copper(II) ion?

    Model answer

    Chloride ions are much larger than water molecules, so only four of them can pack around the small Cu²⁺ ion without repelling one another too strongly. The complex therefore changes from six-coordinate octahedral to four-coordinate tetrahedral.

  4. 4

    The yellow solution formed when concentrated hydrochloric acid is added to copper(II) sulfate turns pale blue again when water is poured in. Explain why.

    Model answer

    The change is a reversible equilibrium, [Cu(H₂O)₆]²⁺ + 4Cl⁻ ⇌ [CuCl₄]²⁻ + 6H₂O. Adding water raises the concentration of water and dilutes the chloride ions, so by Le Chatelier's principle the position of equilibrium shifts to the left and the hexaaqua ion re-forms.

  5. 5

    Concentrated hydrochloric acid is added to a pink solution of cobalt(II) chloride. Write the equation and state the colour change.

    Model answer

    [Co(H₂O)₆]²⁺(aq) + 4Cl⁻(aq) ⇌ [CoCl₄]²⁻(aq) + 6H₂O(l). The solution changes from pink to blue.

  6. 6

    Confirm that the equation [Co(H₂O)₆]²⁺ + 4Cl⁻ ⇌ [CoCl₄]²⁻ + 6H₂O balances for charge.

    Model answer

    On the left the charge is +2 from the complex plus 4 × (−1) from the chloride ions, giving −2 overall. On the right the complex carries −2 and the water molecules are neutral, so the total is also −2.

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