WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemistry of the D-Block Transition Metals
Ligand exchange and changes in coordination number
- 3 things to know
- A2 Unit 3
Overview
Recall questions on ligand exchange.
What you need to know
Answer each one before you reveal it.
Concentrated hydrochloric acid is added to a pink solution of cobalt(II) chloride. Write the equation and state the colour change.
Cobalt chloride paper is used to test for water. Describe the colour change and explain it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is meant by ligand exchange?
Model answer
It is a reaction in which one ligand in a complex ion is replaced by another. The new ligand donates a lone pair to the metal in place of the old one, and the oxidation state of the metal is unchanged.
- 2
Concentrated hydrochloric acid is added to a pale blue solution of copper(II) sulfate. Write the equation and describe what is seen.
Model answer
[Cu(H₂O)₆]²⁺(aq) + 4Cl⁻(aq) ⇌ [CuCl₄]²⁻(aq) + 6H₂O(l). The pale blue solution turns yellow, usually passing through green as the mixture contains both ions at once.
- 3
Why does the coordination number fall from six to four when chloride ions replace water ligands on a copper(II) ion?
Model answer
Chloride ions are much larger than water molecules, so only four of them can pack around the small Cu²⁺ ion without repelling one another too strongly. The complex therefore changes from six-coordinate octahedral to four-coordinate tetrahedral.
- 4
The yellow solution formed when concentrated hydrochloric acid is added to copper(II) sulfate turns pale blue again when water is poured in. Explain why.
Model answer
The change is a reversible equilibrium, [Cu(H₂O)₆]²⁺ + 4Cl⁻ ⇌ [CuCl₄]²⁻ + 6H₂O. Adding water raises the concentration of water and dilutes the chloride ions, so by Le Chatelier's principle the position of equilibrium shifts to the left and the hexaaqua ion re-forms.
- 5
Concentrated hydrochloric acid is added to a pink solution of cobalt(II) chloride. Write the equation and state the colour change.
Model answer
[Co(H₂O)₆]²⁺(aq) + 4Cl⁻(aq) ⇌ [CoCl₄]²⁻(aq) + 6H₂O(l). The solution changes from pink to blue.
- 6
Confirm that the equation [Co(H₂O)₆]²⁺ + 4Cl⁻ ⇌ [CoCl₄]²⁻ + 6H₂O balances for charge.
Model answer
On the left the charge is +2 from the complex plus 4 × (−1) from the chloride ions, giving −2 overall. On the right the complex carries −2 and the water molecules are neutral, so the total is also −2.
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