WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemistry of the P-Block
Stability of oxidation states down Groups 3, 4 and 5: change in relative stability
- 3 things to know
- A2 Unit 3
Overview
Thirteen recall questions on stability of oxidation states down Groups 3, 4 and 5: change in relative stability.
What you need to know
Answer each one before you reveal it.
Why is carbon monoxide such a useful reducing agent?
Lead(IV) oxide is warmed with concentrated hydrochloric acid. Write the equation and describe what is seen.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Carbon monoxide reduces iron(III) oxide in the blast furnace. Write the equation and give the oxidation number change for each element that changes.
Model answer
Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g). Iron falls from +3 to 0, so it is reduced; carbon rises from +2 to +4, so carbon monoxide is oxidised and acts as the reducing agent.
- 2
A black solid is heated in a stream of carbon monoxide and turns pink-brown. Identify the reaction and write the equation.
Model answer
Copper(II) oxide is being reduced to copper metal: CuO(s) + CO(g) → Cu(s) + CO₂(g). The black oxide becomes a pink-brown deposit of copper.
- 3
Write an equation for the reduction of lead(II) oxide by carbon monoxide and state what is observed.
Model answer
PbO(s) + CO(g) → Pb(s) + CO₂(g). The yellow solid turns into a grey bead of molten lead on heating.
- 4
Why is carbon monoxide such a useful reducing agent?
Model answer
Carbon is in the +2 state in carbon monoxide, but at the top of Group 4 the +4 state is much the more stable. Carbon monoxide therefore readily loses two electrons to become carbon dioxide, and in doing so reduces the other reactant.
- 5
Explain why carbon dioxide will not act as a reducing agent in the way carbon monoxide does.
Model answer
In carbon dioxide carbon is already in its most stable oxidation state of +4, so it has no tendency to be oxidised further and cannot donate electrons to another species.
- 6
Lead(IV) oxide is warmed with concentrated hydrochloric acid. Write the equation and describe what is seen.
Model answer
PbO₂(s) + 4HCl(aq) → PbCl₂(s) + Cl₂(g) + 2H₂O(l). The dark brown-black solid reacts and a greenish-yellow, choking gas is evolved. In an excess of concentrated acid the lead(II) does not stay as a white solid but dissolves as the chloro-complex [PbCl₄]²⁻, so the mixture clears as the reaction proceeds.
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