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Chemistry of the D-Block Transition Metals

Transition metal ions with aqueous hydroxide

  • 3 things to know
  • A2 Unit 3

Overview

Seventeen recall questions on transition metal ions with aqueous hydroxide.

What you need to know

Answer each one before you reveal it.

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Key term

Four unlabelled solutions contain chromium(III), iron(II), iron(III) and copper(II) ions. Explain how adding excess sodium hydroxide solution to each would identify them.

Key term

Why is it important to add the sodium hydroxide dropwise at first when testing an unknown transition metal solution?

Key term

Write the reaction of the hexaaquairon(III) ion with hydroxide ions as a series of proton transfers.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Sodium hydroxide solution is added dropwise, and then in excess, to a green solution of a chromium(III) salt. Describe what is seen and give the equations.

    Model answer

    A grey-green precipitate of chromium(III) hydroxide forms: Cr³⁺(aq) + 3OH⁻(aq) → Cr(OH)₃(s). In excess alkali it dissolves to give a dark green solution: Cr(OH)₃(s) + 3OH⁻(aq) → [Cr(OH)₆]³⁻(aq).

  2. 2

    Why does the precipitate obtained from chromium(III) ions and sodium hydroxide dissolve when more alkali is added?

    Model answer

    Chromium(III) hydroxide is amphoteric. In excess hydroxide it acts as an acid, accepting three further hydroxide ions to form the soluble hexahydroxochromate(III) ion, so the solid dissolves and a dark green solution remains.

  3. 3

    Name the ion [Cr(OH)₆]³⁻ and give the coordination number and shape.

    Model answer

    It is the hexahydroxochromate(III) ion. The coordination number is six and the shape is octahedral, with bond angles of 90°.

  4. 4

    What is seen when sodium hydroxide solution is added to a pale green solution of iron(II) sulfate?

    Model answer

    A dirty green precipitate of iron(II) hydroxide forms: Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s). It does not dissolve when excess alkali is added.

  5. 5

    The green precipitate obtained from iron(II) ions and sodium hydroxide slowly turns red-brown at the surface. Explain this and write an equation.

    Model answer

    Oxygen from the air oxidises iron(II) to iron(III): 4Fe(OH)₂(s) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s). Iron(III) hydroxide is red-brown, and because the oxidation starts where air reaches the solid, the surface darkens first.

  6. 6

    Describe what is seen when sodium hydroxide solution is added dropwise, and then in excess, to a yellow-brown solution of iron(III) chloride.

    Model answer

    A red-brown precipitate of iron(III) hydroxide forms: Fe³⁺(aq) + 3OH⁻(aq) → Fe(OH)₃(s). Adding excess alkali makes no difference, as the precipitate is insoluble in excess.

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