WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemistry of the D-Block Transition Metals
Why transition metal complexes are coloured
- 3 things to know
- A2 Unit 3
Overview
Eighteen recall questions on why transition metal complexes are coloured.
What you need to know
Answer each one before you reveal it.
Why are compounds of Sc³⁺ and Zn²⁺ colourless?
What does it mean to say that the colour seen is the complement of the colour absorbed?
Questions from this subtopic
Each one with the model answer underneath.
- 1
In an isolated gaseous metal ion the five d orbitals all have the same energy. Why does that change when ligands approach?
Model answer
The lone pairs on the ligands are regions of negative charge that repel the electrons in the d orbitals. Because the d orbitals point in different directions, some are directed straight at the incoming ligands and others between them, so they are raised in energy by different amounts. The degeneracy is removed and the set splits.
- 2
Describe how the d orbitals split in an octahedral complex.
Model answer
The six ligands approach along the x, y and z axes. The two orbitals that point directly along the axes, d(z²) and d(x²−y²), are repelled most and are raised to a higher energy level, while the three orbitals that point between the axes, d(xy), d(xz) and d(yz), are raised less and form a lower level. The two levels are separated by an energy gap ΔE.
- 3
Explain how the splitting of the d orbitals gives a complex its colour.
Model answer
White light passes through the solution and a d electron in the lower set absorbs a photon whose energy exactly matches the gap ΔE, so the electron is promoted to the upper set. The wavelengths corresponding to that energy are removed from the light, and the colour seen is made up of the wavelengths that are transmitted.
- 4
Write the relationship between the size of the d-orbital splitting and the wavelength of light absorbed.
Model answer
ΔE = hc/λ, where h is the Planck constant, c is the speed of light and λ is the wavelength absorbed. A larger splitting means a shorter wavelength of light is absorbed.
- 5
Why are compounds of Sc³⁺ and Zn²⁺ colourless?
Model answer
Sc³⁺ is 3d⁰ so it has no d electron to promote, and Zn²⁺ is 3d¹⁰ so its d sub-shell is full and there is no vacancy to promote an electron into. Neither can undergo a d–d transition, so neither absorbs visible light.
- 6
What does it mean to say that the colour seen is the complement of the colour absorbed?
Model answer
Only the light that is not absorbed reaches the eye. If a complex removes red light from white light, the remaining transmitted light appears blue-green, so the observed colour is the one opposite the absorbed colour on a colour wheel.
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