WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Simple Equilibria and Acid-Base Reactions
The equilibrium constant Kc
- 3 things to know
- AS Unit 1
Overview
Sixteen recall questions on the equilibrium constant Kc.
What you need to know
Answer each one before you reveal it.
Write the expression for Kc for N₂(g) + 3H₂(g) ⇌ 2NH₃(g) and deduce its units.
Write the expression for Kc for the equilibrium H₂(g) + I₂(g) ⇌ 2HI(g).
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write the expression for Kc for the equilibrium H₂(g) + I₂(g) ⇌ 2HI(g).
Model answer
Kc = [HI]² / ([H₂][I₂]), where each square bracket is the equilibrium concentration in mol dm⁻³.
- 2
Write the expression for Kc for N₂(g) + 3H₂(g) ⇌ 2NH₃(g) and deduce its units.
Model answer
Kc = [NH₃]² / ([N₂][H₂]³). The units are (mol dm⁻³)² divided by (mol dm⁻³)⁴, which simplifies to mol⁻² dm⁶.
- 3
Why does the equilibrium constant for H₂(g) + I₂(g) ⇌ 2HI(g) have no units?
Model answer
There are two concentration terms on the top and two on the bottom, so the units of mol dm⁻³ cancel completely and Kc is simply a number.
- 4
An equilibrium mixture of hydrogen, iodine and hydrogen iodide contains [H₂] = 0.0200 mol dm⁻³, [I₂] = 0.0200 mol dm⁻³ and [HI] = 0.140 mol dm⁻³. Calculate Kc for H₂(g) + I₂(g) ⇌ 2HI(g).
Model answer
Kc = [HI]² / ([H₂][I₂]) = (0.140)² / (0.0200 × 0.0200) = 0.0196 / (4.00 × 10⁻⁴) = 49.0. The units cancel, so Kc = 49.0 with no units.
- 5
At a certain temperature an equilibrium mixture contains [N₂] = 0.500 mol dm⁻³, [H₂] = 1.00 mol dm⁻³ and [NH₃] = 0.200 mol dm⁻³. Calculate Kc for N₂(g) + 3H₂(g) ⇌ 2NH₃(g), including units.
Model answer
Kc = [NH₃]² / ([N₂][H₂]³) = (0.200)² / (0.500 × (1.00)³) = 0.0400 / 0.500 = 0.0800 mol⁻² dm⁶.
- 6
2.00 mol of hydrogen and 2.00 mol of iodine are sealed in a 5.00 dm³ vessel. At equilibrium 3.20 mol of hydrogen iodide is present. Calculate Kc for H₂(g) + I₂(g) ⇌ 2HI(g).
Model answer
Forming 3.20 mol of HI uses 1.60 mol of H₂ and 1.60 mol of I₂, so 0.40 mol of each remains. Dividing by 5.00 dm³ gives [H₂] = [I₂] = 0.080 mol dm⁻³ and [HI] = 0.640 mol dm⁻³. Kc = (0.640)² / (0.080 × 0.080) = 0.4096 / (6.4 × 10⁻³) = 64. Kc = 64, with no units.
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