WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Organic Synthesis and Analysis
High-resolution ¹H NMR and the elucidation of structure: low- and high-resolution proton NMR
- 1 thing to know
- A2 Unit 4
Overview
What low- and high-resolution ¹H NMR spectra show, what causes a peak, the n+1 rule and splitting patterns with their line ratios, and using integration traces to find the ratio of hydrogen environments.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What information does a low-resolution ¹H NMR spectrum give?
Model answer
It gives the number of different chemical environments the hydrogen atoms occupy, shown by the number of separate peaks. It also gives the chemical shift of each peak, which suggests what kind of group the hydrogen atoms are attached to, and from the relative areas of the peaks it gives the ratio of the numbers of hydrogen atoms in each environment.
- 2
What extra information does a high-resolution spectrum add?
Model answer
At high resolution each peak may be seen to consist of a group of closely spaced lines rather than a single line. The number of lines in each group tells you how many hydrogen atoms sit on the carbon atoms next to the one carrying the hydrogens that produce the peak. That reveals how the fragments of the molecule are joined to one another.
- 3
What causes a peak in a ¹H NMR spectrum to be split into several lines?
Model answer
Each hydrogen nucleus behaves as a tiny magnet, and in the applied field it can be aligned either with the field or against it. A hydrogen atom on a neighbouring carbon therefore adds a very small amount to, or subtracts a very small amount from, the field felt by the absorbing hydrogen. Different combinations of the neighbours' orientations give slightly different total fields, so the absorbing hydrogens resonate at slightly different frequencies and the signal appears as several lines instead of one.
- 4
State the n+1 rule.
Model answer
If a hydrogen atom, or a group of equivalent hydrogen atoms, has n hydrogen atoms on the adjacent carbon atoms, and those n are equivalent to each other, then its signal is split into n + 1 lines.
- 5
Predict the splitting pattern of the ¹H NMR spectrum of bromoethane, CH₃CH₂Br.
Model answer
There are two environments. The CH₃ hydrogens have two hydrogens on the adjacent carbon, so n = 2 and their signal is a triplet of three lines, and being three hydrogens it integrates for 3H at about δ 1.7. The CH₂ hydrogens have three hydrogens on the adjacent carbon, so n = 3 and their signal is a quartet of four lines, integrating for 2H at about δ 3.4, shifted downfield by the electronegative bromine.
- 6
Why does a triplet have relative line intensities 1:2:1 and a quartet 1:3:3:1?
Model answer
The intensities count the number of ways the neighbouring spins can combine to give each total field. With two neighbours there is one way for both to be aligned with the field and one way for both to be against, but two ways for one of each, so the middle line is twice as intense. With three neighbours the counts are one, three, three and one for three-with, two-with-one-against, one-with-two-against and three-against.
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