WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Core Experiments and Their Chemistry
Gravimetric and acid–base analysis
- 3 things to know
- All units
Overview
Recall questions on Gravimetric analysis and acid–base analysis.
What you need to know
Answer each one before you reveal it.
Why might a gravimetric determination of water of crystallisation give a value that is too low?
Why is the solution acidified with dilute hydrochloric acid before barium chloride is added in a gravimetric sulfate determination?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe how the formula of a hydrated salt can be found by heating it in a crucible.
Model answer
Weigh a clean dry crucible and lid, add the hydrated salt and reweigh, then heat gently, allow the crucible to cool in a desiccator and reweigh. Repeat the heating and weighing until two successive masses agree, and use the loss in mass as the mass of water driven off.
- 2
Why is a sample heated to constant mass in a gravimetric determination?
Model answer
Constant mass shows that no further water or gas is being lost, so the decomposition or dehydration is complete. Stopping after one heating risks leaving some water behind and underestimating the amount of water of crystallisation.
- 3
Why is the crucible cooled in a desiccator rather than in the open laboratory?
Model answer
A hot crucible must be cooled before weighing because warm air currents affect the balance, and an anhydrous salt readily reabsorbs moisture from the air. A desiccator provides a dry atmosphere so that the mass recorded is that of the anhydrous solid.
- 4
Heating 2.50 g of hydrated copper(II) sulfate leaves 1.60 g of the anhydrous salt. Determine the number of molecules of water of crystallisation per formula unit. (Mr of CuSO₄ = 159.6, Mr of H₂O = 18.0)
Model answer
Mass of water lost = 2.50 − 1.60 = 0.90 g, so moles of water = 0.90 / 18.0 = 0.0500 mol. Moles of CuSO₄ = 1.60 / 159.6 = 0.01003 mol. The ratio of water to salt is 0.0500 / 0.01003 = 4.99, so the formula is CuSO₄·5H₂O.
- 5
Why might a gravimetric determination of water of crystallisation give a value that is too low?
Model answer
Heating may have been insufficient, so some water remained in the solid, which makes the measured mass loss too small. The anhydrous solid may also have absorbed moisture from the air before it was reweighed, which has the same effect.
- 6
Why can heating a hydrated salt too strongly give a result that is too high?
Model answer
Overheating can decompose the anhydrous salt itself, driving off further products such as sulfur trioxide or oxygen. The extra mass lost is then wrongly counted as water of crystallisation.
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