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Redox and Standard Electrode Potential

Electron transfer and oxidation numbers

  • 3 things to know
  • A2 Unit 3

Overview

Recall questions on oxidising agent, reducing agent and disproportionation.

What you need to know

Answer each one before you reveal it.

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Numbers

In the reaction 2Fe³⁺(aq) + 2I⁻(aq) → 2Fe²⁺(aq) + I₂(aq), state the oxidation number change for each element that changes and identify the reducing agent.

Key term

What rules are used to assign oxidation numbers?

Key term

How many electrons are gained per manganese when MnO₄⁻ becomes Mn²⁺, how many per chromium when Cr₂O₇²⁻ becomes Cr³⁺, and what is the oxidation number of chlorine in ClO₃⁻?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What do oxidation and reduction mean in terms of electrons?

    Model answer

    Oxidation is the loss of electrons by a species and reduction is the gain of electrons by a species. The two always happen together, since the electrons lost by one species must be gained by another.

  2. 2

    What is an oxidising agent?

    Model answer

    A species that accepts electrons from another substance and so brings about the oxidation of that substance. In doing so the oxidising agent is itself reduced.

  3. 3

    What is a reducing agent?

    Model answer

    A species that donates electrons to another substance and so brings about the reduction of that substance. In doing so the reducing agent is itself oxidised.

  4. 4

    In the reaction 2Fe³⁺(aq) + 2I⁻(aq) → 2Fe²⁺(aq) + I₂(aq), state the oxidation number change for each element that changes and identify the reducing agent.

    Model answer

    Iron falls from +3 in Fe³⁺ to +2 in Fe²⁺, gaining one electron per ion, so iron(III) is reduced. Iodine rises from −1 in I⁻ to 0 in I₂, losing one electron per ion, so iodide is oxidised. The iodide ion is therefore the reducing agent and the iron(III) ion the oxidising agent.

  5. 5

    What rules are used to assign oxidation numbers?

    Model answer

    An uncombined element is zero. A simple monatomic ion takes the value of its charge. Fluorine is always −1; oxygen is normally −2 but −1 in peroxides; hydrogen is normally +1 but −1 in metal hydrides. Group 1 metals are +1, Group 2 are +2 and aluminium is +3. The values in a neutral compound sum to zero, and in a polyatomic ion they sum to the charge on the ion.

  6. 6

    Work out the oxidation number of manganese in MnO₄⁻.

    Model answer

    Each oxygen is −2, giving 4 × (−2) = −8. The total must equal the ionic charge of −1, so the manganese must be +7 since +7 − 8 = −1.

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