WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Halogenoalkanes
Elimination to form alkenes
- 3 things to know
- AS Unit 2
Overview
Recall questions on elimination reaction.
What you need to know
Answer each one before you reveal it.
What reagent and conditions are needed to convert a halogenoalkane into an alkene?
What is an elimination reaction?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is an elimination reaction?
Model answer
An elimination reaction is one in which a small molecule is removed from a single organic molecule, with two atoms or groups lost from adjacent carbon atoms so that a double bond is formed between them.
- 2
What reagent and conditions are needed to convert a halogenoalkane into an alkene?
Model answer
The halogenoalkane is heated under reflux with a concentrated solution of potassium hydroxide dissolved in ethanol rather than in water.
- 3
Write the equation for the elimination reaction of 1-bromopropane with ethanolic potassium hydroxide and name the organic product.
Model answer
The equation is CH₃CH₂CH₂Br + KOH → CH₃CH=CH₂ + KBr + H₂O, and the organic product is propene.
- 4
In an elimination reaction of a halogenoalkane, what role does the hydroxide ion play?
Model answer
It acts as a base rather than as a nucleophile, removing a hydrogen atom as H⁺ from the carbon next to the one carrying the halogen instead of bonding to the carbon itself.
- 5
Describe the mechanism by which ethanolic hydroxide converts 1-bromopropane into propene, saying where each curly arrow starts and ends.
Model answer
Three arrows are needed. The first starts at a lone pair on the hydroxide oxygen and ends at a hydrogen atom on the carbon adjacent to the C–Br carbon. The second starts at that C–H bonding pair and ends between the two carbon atoms, forming the π-bond of the C=C. The third starts at the C–Br bonding pair and ends on the bromine, which leaves heterolytically as a bromide ion. The products are propene and water.
- 6
Which two small molecules or ions are removed from 1-bromopropane when it forms propene?
Model answer
A hydrogen atom is removed from carbon 2 and a bromine atom from carbon 1; overall the elements of hydrogen bromide are lost, appearing as water and a bromide ion when a base is used.
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