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Halogenoalkanes

Elimination to form alkenes

  • 3 things to know
  • AS Unit 2

Overview

Recall questions on elimination reaction.

What you need to know

Answer each one before you reveal it.

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Key term

Why is ethanol rather than water used as the solvent when elimination is wanted?

Key term

What reagent and conditions are needed to convert a halogenoalkane into an alkene?

Key term

What is an elimination reaction?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is an elimination reaction?

    Model answer

    An elimination reaction is one in which a small molecule is removed from a single organic molecule, with two atoms or groups lost from adjacent carbon atoms so that a double bond is formed between them.

  2. 2

    What reagent and conditions are needed to convert a halogenoalkane into an alkene?

    Model answer

    The halogenoalkane is heated under reflux with a concentrated solution of potassium hydroxide dissolved in ethanol rather than in water.

  3. 3

    Write the equation for the elimination reaction of 1-bromopropane with ethanolic potassium hydroxide and name the organic product.

    Model answer

    The equation is CH₃CH₂CH₂Br + KOH → CH₃CH=CH₂ + KBr + H₂O, and the organic product is propene.

  4. 4

    In an elimination reaction of a halogenoalkane, what role does the hydroxide ion play?

    Model answer

    It acts as a base rather than as a nucleophile, removing a hydrogen atom as H⁺ from the carbon next to the one carrying the halogen instead of bonding to the carbon itself.

  5. 5

    Describe the mechanism by which ethanolic hydroxide converts 1-bromopropane into propene, saying where each curly arrow starts and ends.

    Model answer

    Three arrows are needed. The first starts at a lone pair on the hydroxide oxygen and ends at a hydrogen atom on the carbon adjacent to the C–Br carbon. The second starts at that C–H bonding pair and ends between the two carbon atoms, forming the π-bond of the C=C. The third starts at the C–Br bonding pair and ends on the bromine, which leaves heterolytically as a bromide ion. The products are propene and water.

  6. 6

    Which two small molecules or ions are removed from 1-bromopropane when it forms propene?

    Model answer

    A hydrogen atom is removed from carbon 2 and a bromine atom from carbon 1; overall the elements of hydrogen bromide are lost, appearing as water and a bromide ion when a base is used.

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