WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
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Amines
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Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Amines
Coupling reactions and azo dyes: role of the —N=N— chromophore in azo dyes
- 3 things to know
- A2 Unit 4
Overview
Recall questions on chromophore.
What you need to know
Answer each one before you reveal it.
Why does the colour disappear if a saturated –CH₂CH₂– group is inserted between the azo group and one of the rings?
Describe in words the structure of 4-hydroxyazobenzene.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is meant by a chromophore?
Model answer
It is the group of atoms within a molecule that is responsible for absorbing light in the visible region and so for the molecule's colour. In an azo dye the chromophore is the –N=N– group together with the aromatic rings joined to it.
- 2
How does the –N=N– group give an azo compound its strong colour?
Model answer
The nitrogen–nitrogen double bond joins the two aromatic rings so that their pi systems and the pi bond of the azo group merge into one delocalised system stretching across the whole molecule. Electrons in such an extended system are promoted by relatively little energy, and the energy available happens to lie in the visible part of the spectrum.
- 3
Why is the colour of an azo dye much more intense than that of a compound containing an isolated N=N group?
Model answer
An isolated nitrogen–nitrogen double bond has only a small pi system, so the energy needed to promote its electrons is large and the absorption falls in the ultraviolet. Once the group is flanked by two aromatic rings the delocalisation extends over the whole molecule, the energy gap drops into the visible range and strong absorption of visible light results.
- 4
How can the shade of an azo dye be altered by the chemist?
Model answer
Groups such as –OH, –NH₂ and –NO₂ attached to the rings feed electron density into or draw it out of the delocalised system, which alters the size of the energy gap and so shifts the wavelength absorbed. Choosing a different aromatic component, for instance a naphthalene ring instead of a benzene ring, also lengthens the delocalised system and deepens the colour.
- 5
Why does the colour disappear if a saturated –CH₂CH₂– group is inserted between the azo group and one of the rings?
Model answer
The saturated carbon atoms have no p orbitals available for sideways overlap, so the delocalised system can no longer run from one ring to the other. The pi electrons are confined to smaller separate regions, the energy gap rises, and the absorption moves out of the visible range into the ultraviolet.
- 6
Why must the atoms around the –N=N– link lie in the same plane?
Model answer
Delocalisation depends on the p orbitals of the nitrogen atoms and of the ring carbons being parallel so that they can overlap sideways. If the molecule twists about the bonds to the azo group that overlap is reduced, the delocalised system is broken up and the absorption shifts away from the visible region.
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