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Chemistry of the P-Block

Group 4 oxides and chlorides, and lead in solution: structure

  • 3 things to know
  • A2 Unit 3

Overview

Fourteen recall questions on group 4 oxides and chlorides, and lead in solution: structure.

What you need to know

Answer each one before you reveal it.

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Key term

Describe the structure and bonding in carbon dioxide.

Key term

Why is carbon dioxide a gas at room temperature while silicon dioxide is a solid melting above 1600 °C?

Key term

Carbon dioxide contains polar bonds but is a non-polar molecule. Explain.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the structure and bonding in carbon dioxide.

    Model answer

    Carbon dioxide is simple molecular. Each molecule is a linear O=C=O unit with two strong covalent double bonds, and separate molecules are attracted only by weak van der Waals forces.

  2. 2

    Why is carbon dioxide a gas at room temperature while silicon dioxide is a solid melting above 1600 °C?

    Model answer

    Carbon dioxide is made of small discrete molecules held together only by weak van der Waals forces, which need very little energy to overcome. Silicon dioxide is a giant covalent lattice in which melting requires many strong Si–O bonds to be broken.

  3. 3

    Carbon dioxide contains polar bonds but is a non-polar molecule. Explain.

    Model answer

    Oxygen is more electronegative than carbon, so each C=O bond is polar. The molecule is linear and symmetrical, so the two bond dipoles are equal and point in exactly opposite directions and therefore cancel, leaving no overall dipole.

  4. 4

    State the physical state and appearance of carbon dioxide, and what happens to solid carbon dioxide on warming at atmospheric pressure.

    Model answer

    It is a colourless, odourless gas that is denser than air. Solid carbon dioxide sublimes directly to the gas at about −78 °C without melting.

  5. 5

    Carbon dioxide dissolves in water to give a weakly acidic solution. Write equations to show why.

    Model answer

    CO₂(g) + H₂O(l) ⇌ H₂CO₃(aq), and then H₂CO₃(aq) ⇌ H⁺(aq) + HCO₃⁻(aq). Only a small fraction of the dissolved gas forms carbonic acid and only a little of that dissociates, so the solution is weakly acidic with a pH of about 4 to 5.

  6. 6

    Write the ionic equation for carbon dioxide reacting with excess sodium hydroxide solution.

    Model answer

    CO₂(g) + 2OH⁻(aq) → CO₃²⁻(aq) + H₂O(l). Carbon dioxide is an acidic oxide, so it is neutralised by alkali to give the carbonate.

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