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Organic Synthesis and Analysis

High-resolution ¹H NMR and the elucidation of structure: chemical shift, TMS, solvents and D₂O exchange

  • 3 things to know
  • A2 Unit 4

Overview

Chemical shift and the TMS standard, why deuterated solvents are used, identifying -OH and -NH protons by D₂O exchange, and predicting the number of peaks and spectra for simple compounds.

What you need to know

Answer each one before you reveal it.

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Key term

Why is tetramethylsilane chosen as the reference compound for ¹H NMR?

Key term

Why must a ¹H NMR sample be dissolved in a solvent such as trichloromethane in which the hydrogen has been replaced by deuterium?

Key term

Why does the hydrogen of an −OH group usually appear as a broad single line that is neither split nor splits its neighbours?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is the chemical shift δ, and against what standard is it measured?

    Model answer

    The chemical shift is the position of a signal, expressed as a shift in frequency relative to that of a standard divided by the operating frequency of the spectrometer, quoted in parts per million. The standard is tetramethylsilane, whose signal is defined as δ 0. Measuring it as a ratio in this way makes the value independent of the strength of the spectrometer's magnet.

  2. 2

    Why is tetramethylsilane chosen as the reference compound for ¹H NMR?

    Model answer

    All twelve of its hydrogen atoms are in the same environment, so it gives a single sharp peak. That peak lies clear of almost all other signals, at one end of the usual range, so it does not obscure them. It is also chemically inert so it does not react with the sample, and it is volatile so it is easily removed afterwards.

  3. 3

    Why must a ¹H NMR sample be dissolved in a solvent such as trichloromethane in which the hydrogen has been replaced by deuterium?

    Model answer

    The solvent is present in far greater amount than the sample, so if it contained ordinary hydrogen its own signal would be enormous and would swamp the sample's peaks. Deuterium does not absorb at the frequencies used for ¹H NMR, so a deuteriated solvent gives no peak in the spectrum and leaves the sample's signals clear.

  4. 4

    A ¹H NMR spectrum is recorded, and then recorded a second time after the sample has been shaken with deuterium oxide. One of the peaks has disappeared. What does this tell you?

    Model answer

    The peak that vanished was due to a hydrogen attached to oxygen or nitrogen, such as the hydrogen of an −OH or an −NH group. These hydrogens exchange rapidly with the deuterium of the D₂O, so they are replaced by deuterium, which does not absorb. The disappearance of the peak identifies the compound as containing such a group and also identifies which peak it was.

  5. 5

    Why does the hydrogen of an −OH group usually appear as a broad single line that is neither split nor splits its neighbours?

    Model answer

    The −OH hydrogen is exchanged rapidly between molecules, so it spends only a very short time attached to any one molecule. The coupling to neighbouring hydrogens is averaged out over these rapid exchanges, so no splitting is resolved in either direction, and the rapid exchange broadens the line.

  6. 6

    Why does a hydrogen atom attached to a carbon that is bonded to an electronegative atom absorb at a higher chemical shift?

    Model answer

    The circulating electrons around a hydrogen nucleus generate a small field opposing the applied field, so the nucleus feels slightly less than the applied field; this is shielding. An electronegative atom nearby withdraws electron density from the C−H bond, so there is less electron density around the hydrogen and it is less shielded. It therefore feels more of the applied field and resonates further downfield, at a higher value of δ.

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