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Chemistry of the P-Block

Chlorine, chlorate and the sodium halides: chlorine with water and with cold and hot alkali

  • 3 things to know
  • A2 Unit 3

Overview

Chlorine with cold dilute and hot concentrated sodium hydroxide, the disproportionation of chlorate(I), chlorine with water and its effect on indicator, and oxidation numbers and half-equations for these reactions.

What you need to know

Answer each one before you reveal it.

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Key term

Give the ionic equation for chlorine reacting with cold dilute alkali and show that it is a disproportionation.

Numbers

What is seen when chlorine gas is bubbled into cold dilute sodium hydroxide solution?

Key term

Balance the ionic equation for chlorine with cold alkali and confirm the charge balance.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    When chlorine reacts with cold aqueous sodium hydroxide, chlorine appears in the products at both −1 and +1. Explain why this is called disproportionation.

    Model answer

    The same element is oxidised and reduced in one reaction: some chlorine atoms rise from 0 to +1 in the chlorate(I) ion while others fall from 0 to −1 in the chloride ion.

  2. 2

    Write the equation for the reaction of chlorine with cold dilute sodium hydroxide solution and name the products.

    Model answer

    Cl₂(g) + 2NaOH(aq) → NaCl(aq) + NaClO(aq) + H₂O(l). The products are sodium chloride and sodium chlorate(I), which is the active ingredient of household bleach.

  3. 3

    Give the ionic equation for chlorine reacting with cold dilute alkali and show that it is a disproportionation.

    Model answer

    Cl₂ + 2OH⁻ → Cl⁻ + ClO⁻ + H₂O. Chlorine starts at oxidation number 0; in Cl⁻ it is −1, so it has been reduced, and in ClO⁻ it is +1, so it has been oxidised. The same element is both oxidised and reduced, so this is disproportionation.

  4. 4

    What is seen when chlorine gas is bubbled into cold dilute sodium hydroxide solution?

    Model answer

    The greenish-yellow gas is absorbed and the solution stays essentially colourless, developing the faint pale yellow tinge and sharp smell of chlorate(I). No gas is given off.

  5. 5

    Write the equation for the reaction of chlorine with hot concentrated sodium hydroxide solution.

    Model answer

    3Cl₂(g) + 6NaOH(aq) → 5NaCl(aq) + NaClO₃(aq) + 3H₂O(l). The products are sodium chloride and sodium chlorate(V).

  6. 6

    Give the ionic equation for chlorine with hot concentrated alkali and state the oxidation numbers of chlorine in the products.

    Model answer

    3Cl₂ + 6OH⁻ → 5Cl⁻ + ClO₃⁻ + 3H₂O. Chlorine is −1 in the chloride ion and +5 in the chlorate(V) ion, having started at 0 in chlorine.

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