WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemistry of the P-Block
Chlorine, chlorate and the sodium halides: chlorine with water and with cold and hot alkali
- 3 things to know
- A2 Unit 3
Overview
Chlorine with cold dilute and hot concentrated sodium hydroxide, the disproportionation of chlorate(I), chlorine with water and its effect on indicator, and oxidation numbers and half-equations for these reactions.
What you need to know
Answer each one before you reveal it.
What is seen when chlorine gas is bubbled into cold dilute sodium hydroxide solution?
Balance the ionic equation for chlorine with cold alkali and confirm the charge balance.
Questions from this subtopic
Each one with the model answer underneath.
- 1
When chlorine reacts with cold aqueous sodium hydroxide, chlorine appears in the products at both −1 and +1. Explain why this is called disproportionation.
Model answer
The same element is oxidised and reduced in one reaction: some chlorine atoms rise from 0 to +1 in the chlorate(I) ion while others fall from 0 to −1 in the chloride ion.
- 2
Write the equation for the reaction of chlorine with cold dilute sodium hydroxide solution and name the products.
Model answer
Cl₂(g) + 2NaOH(aq) → NaCl(aq) + NaClO(aq) + H₂O(l). The products are sodium chloride and sodium chlorate(I), which is the active ingredient of household bleach.
- 3
Give the ionic equation for chlorine reacting with cold dilute alkali and show that it is a disproportionation.
Model answer
Cl₂ + 2OH⁻ → Cl⁻ + ClO⁻ + H₂O. Chlorine starts at oxidation number 0; in Cl⁻ it is −1, so it has been reduced, and in ClO⁻ it is +1, so it has been oxidised. The same element is both oxidised and reduced, so this is disproportionation.
- 4
What is seen when chlorine gas is bubbled into cold dilute sodium hydroxide solution?
Model answer
The greenish-yellow gas is absorbed and the solution stays essentially colourless, developing the faint pale yellow tinge and sharp smell of chlorate(I). No gas is given off.
- 5
Write the equation for the reaction of chlorine with hot concentrated sodium hydroxide solution.
Model answer
3Cl₂(g) + 6NaOH(aq) → 5NaCl(aq) + NaClO₃(aq) + 3H₂O(l). The products are sodium chloride and sodium chlorate(V).
- 6
Give the ionic equation for chlorine with hot concentrated alkali and state the oxidation numbers of chlorine in the products.
Model answer
3Cl₂ + 6OH⁻ → 5Cl⁻ + ClO₃⁻ + 3H₂O. Chlorine is −1 in the chloride ion and +5 in the chlorate(V) ion, having started at 0 in chlorine.
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