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Core Experiments and Their Chemistry

Equilibrium constants and following a titration with a pH probe

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Overview

Sixteen recall questions on equilibrium constants and following a titration with a pH probe.

What you need to know

Answer each one before you reveal it.

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Key term

Why is the equivalence point of the titration of ethanoic acid with sodium hydroxide above pH 7?

Key term

Why must the pH probe be kept fully immersed and the solution stirred throughout a pH titration?

Key term

Why must an equilibrium mixture be kept at a constant temperature while it stands before analysis?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe how the equilibrium constant for the esterification of ethanoic acid with ethanol can be determined.

    Model answer

    Seal known amounts of the acid, the alcohol and a small measured amount of acid catalyst in a stoppered container and leave the mixture at constant temperature for about a week to reach equilibrium. Then titrate the whole mixture with standard sodium hydroxide to find the total acid present, subtract the catalyst, and use the amount of ethanoic acid remaining to deduce the equilibrium amounts of all four substances.

  2. 2

    Why must the amount of acid catalyst be measured accurately and allowed for in the calculation?

    Model answer

    The catalyst is a strong acid and is titrated along with the ethanoic acid left at equilibrium, so it inflates the titre. A separate titration of the same amount of catalyst alone, or subtraction of the known amount, gives the ethanoic acid figure that the calculation needs.

  3. 3

    A mixture initially containing 1.00 mol of ethanoic acid and 1.00 mol of ethanol is found at equilibrium to contain 0.33 mol of ethanoic acid. Calculate Kc for the esterification.

    Model answer

    Since 0.67 mol of acid has reacted, the equilibrium amounts are 0.33 mol acid, 0.33 mol ethanol, 0.67 mol ester and 0.67 mol water. Kc = (0.67 × 0.67) / (0.33 × 0.33) = 0.4489 / 0.1089 = 4.1.

  4. 4

    Why does the total volume of the mixture not need to be known in this determination?

    Model answer

    There are two moles of substance on each side of the equation, so the volume terms in the concentration expression cancel. Kc can therefore be calculated from the equilibrium amounts in moles alone, and it is dimensionless in this case.

  5. 5

    Why is the equilibrium mixture titrated quickly and, if possible, cooled and diluted first?

    Model answer

    Removing ethanoic acid by neutralisation disturbs the equilibrium, so the ester begins to hydrolyse and release more acid during the titration. Cooling and diluting slow that reaction down enough for a meaningful end point to be reached.

  6. 6

    How would you show experimentally that a mixture has actually reached equilibrium?

    Model answer

    Take samples at intervals and titrate them; when successive titres no longer change, the composition is constant and equilibrium has been reached. Stronger evidence comes from starting a second mixture from the opposite side, using the ester and water, and showing that it reaches the same value of Kc.

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