WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Core Experiments and Their Chemistry
Equilibrium constants and following a titration with a pH probe
- 3 things to know
- All units
Overview
Sixteen recall questions on equilibrium constants and following a titration with a pH probe.
What you need to know
Answer each one before you reveal it.
Why must the pH probe be kept fully immersed and the solution stirred throughout a pH titration?
Why must an equilibrium mixture be kept at a constant temperature while it stands before analysis?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe how the equilibrium constant for the esterification of ethanoic acid with ethanol can be determined.
Model answer
Seal known amounts of the acid, the alcohol and a small measured amount of acid catalyst in a stoppered container and leave the mixture at constant temperature for about a week to reach equilibrium. Then titrate the whole mixture with standard sodium hydroxide to find the total acid present, subtract the catalyst, and use the amount of ethanoic acid remaining to deduce the equilibrium amounts of all four substances.
- 2
Why must the amount of acid catalyst be measured accurately and allowed for in the calculation?
Model answer
The catalyst is a strong acid and is titrated along with the ethanoic acid left at equilibrium, so it inflates the titre. A separate titration of the same amount of catalyst alone, or subtraction of the known amount, gives the ethanoic acid figure that the calculation needs.
- 3
A mixture initially containing 1.00 mol of ethanoic acid and 1.00 mol of ethanol is found at equilibrium to contain 0.33 mol of ethanoic acid. Calculate Kc for the esterification.
Model answer
Since 0.67 mol of acid has reacted, the equilibrium amounts are 0.33 mol acid, 0.33 mol ethanol, 0.67 mol ester and 0.67 mol water. Kc = (0.67 × 0.67) / (0.33 × 0.33) = 0.4489 / 0.1089 = 4.1.
- 4
Why does the total volume of the mixture not need to be known in this determination?
Model answer
There are two moles of substance on each side of the equation, so the volume terms in the concentration expression cancel. Kc can therefore be calculated from the equilibrium amounts in moles alone, and it is dimensionless in this case.
- 5
Why is the equilibrium mixture titrated quickly and, if possible, cooled and diluted first?
Model answer
Removing ethanoic acid by neutralisation disturbs the equilibrium, so the ester begins to hydrolyse and release more acid during the titration. Cooling and diluting slow that reaction down enough for a meaningful end point to be reached.
- 6
How would you show experimentally that a mixture has actually reached equilibrium?
Model answer
Take samples at intervals and titrate them; when successive titres no longer change, the composition is constant and equilibrium has been reached. Stronger evidence comes from starting a second mixture from the opposite side, using the ester and water, and showing that it reaches the same value of Kc.
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