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Chemical Calculations

Concentration, solubility and titration calculations: stoichiometry and the limiting reagent

  • 3 things to know
  • AS Unit 1

Overview

Recall questions on stoichiometry and the limiting reagent.

What you need to know

Answer each one before you reveal it.

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Key term

What is stoichiometry, and where do you find the information you need to use it?

Key term

0.243 g of magnesium is added to an excess of dilute hydrochloric acid. What volume of hydrogen is produced at room temperature and pressure?

Key term

What volume of 1.00 mol dm⁻³ hydrochloric acid is needed to react completely with 0.243 g of magnesium?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why must a temperature always be quoted alongside a solubility?

    Model answer

    Solubility changes with temperature, usually rising as the temperature rises for a solid in water. A figure with no temperature attached is therefore meaningless as a description of the system.

  2. 2

    What is stoichiometry, and where do you find the information you need to use it?

    Model answer

    Stoichiometry is the fixed ratio in which substances react and are produced. The ratio is read directly from the coefficients of the balanced equation, so the equation must be correct before any calculation of reacting quantities can begin.

  3. 3

    Set out the general route for calculating the mass of a product from the mass of a reactant.

    Model answer

    Convert the known mass to an amount using n = m ÷ M, apply the mole ratio from the balanced equation to get the amount of the other substance, then convert back with m = n × M. Every step should carry its units so that mistakes are visible.

  4. 4

    0.243 g of magnesium is added to an excess of dilute hydrochloric acid. What volume of hydrogen is produced at room temperature and pressure?

    Model answer

    The equation is Mg + 2HCl → MgCl₂ + H₂. n(Mg) = 0.243 ÷ 24.3 = 0.0100 mol, and the ratio of Mg to H₂ is 1 : 1, so n(H₂) = 0.0100 mol. At room conditions, 298 K, the volume is 0.0100 × 24.5 = 0.245 dm³, that is 245 cm³.

  5. 5

    What volume of 1.00 mol dm⁻³ hydrochloric acid is needed to react completely with 0.243 g of magnesium?

    Model answer

    n(Mg) = 0.243 ÷ 24.3 = 0.0100 mol, and Mg + 2HCl → MgCl₂ + H₂ requires two moles of acid per mole of magnesium, so n(HCl) = 0.0200 mol. V = n ÷ c = 0.0200 ÷ 1.00 = 0.0200 dm³, which is 20.0 cm³.

  6. 6

    10.0 g of calcium carbonate is heated until it fully decomposes. What mass of calcium oxide is formed?

    Model answer

    The equation is CaCO₃ → CaO + CO₂. n(CaCO₃) = 10.0 ÷ 100.1 = 0.0999 mol, and the ratio is 1 : 1, so n(CaO) = 0.0999 mol. With M(CaO) = 56.1 g mol⁻¹ the mass is 0.0999 × 56.1 = 5.60 g, to three significant figures.

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