WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Aromaticity
Aromatic stability and resistance to addition
- 3 things to know
- A2 Unit 4
Overview
Recall questions on Aromatic stability and resistance to addition.
What you need to know
Answer each one before you reveal it.
Why does benzene not decolourise acidified potassium manganate(VII) under conditions that oxidise an alkene?
Under what conditions will benzene undergo addition with chlorine, and what is the product?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is benzene more stable than a model with three isolated double bonds would suggest?
Model answer
Delocalising the six pi electrons over all six carbon atoms lowers the total energy of the molecule below that of a structure with three separate localised double bonds. Spreading charge over a larger volume always reduces the repulsion between electrons and lets each electron be attracted by more than two nuclei.
- 2
The enthalpy change of hydrogenation of cyclohexene is −120 kJ mol⁻¹. What value would you predict for a molecule with three isolated double bonds in a six-membered ring?
Model answer
Three times the value for one double bond, so 3 × (−120) = −360 kJ mol⁻¹, on the assumption that each double bond behaves independently of the others.
- 3
Benzene actually has an enthalpy change of hydrogenation of −208 kJ mol⁻¹. Calculate the delocalisation energy and explain what it means.
Model answer
The predicted value for three isolated double bonds is −360 kJ mol⁻¹, so the difference is −208 − (−360) = 152 kJ mol⁻¹. Benzene releases 152 kJ mol⁻¹ less energy than expected, which means it started 152 kJ mol⁻¹ lower in energy than the hypothetical localised structure. That energy gap is the extra stability conferred by delocalisation.
- 4
Write the equation for the complete hydrogenation of benzene and state the conditions.
Model answer
C₆H₆ + 3H₂ → C₆H₁₂, giving cyclohexane. It requires a nickel catalyst, a temperature of about 150 to 200 °C and a raised pressure, conditions far more forcing than the room-temperature hydrogenation of an alkene.
- 5
Why does benzene resist addition reactions?
Model answer
An addition reaction would convert two of the ring carbons to a saturated arrangement and break the continuous ring of overlapping p orbitals, destroying the delocalised system. The 152 kJ mol⁻¹ of extra stability would be lost, so the reaction is energetically unfavourable and the activation energy is high.
- 6
Why is substitution the characteristic reaction of arenes rather than addition?
Model answer
In a substitution the hydrogen on one carbon is replaced but that carbon keeps its p orbital, so the delocalised ring survives intact and the aromatic stabilisation is retained in the product. Addition would sacrifice it, so substitution is the energetically preferred route.
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