WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Redox Reactions
Copper, iodide and thiosulfate
- 3 things to know
- A2 Unit 3
Overview
Recall questions on Copper, iodide and thiosulfate.
What you need to know
Answer each one before you reveal it.
Use oxidation numbers to show that the reaction of copper(II) with iodide is a redox reaction.
Why is an excess of potassium iodide added when copper(II) ions are treated with iodide?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the equation for the reaction between copper(II) ions and iodide ions?
Model answer
2Cu²⁺(aq) + 4I⁻(aq) → 2CuI(s) + I₂(aq). The charge is +4 − 4 = 0 on the left and 0 on the right.
- 2
What is seen when an excess of potassium iodide solution is added to a solution of a copper(II) salt?
Model answer
A white or cream precipitate of copper(I) iodide forms, and the solution turns brown because iodine has been liberated. The mixture appears as a brown liquid over a pale solid.
- 3
Use oxidation numbers to show that the reaction of copper(II) with iodide is a redox reaction.
Model answer
Copper falls from +2 in Cu²⁺ to +1 in CuI, so it is reduced. Iodine rises from −1 in I⁻ to 0 in I₂, so iodide is oxidised. Electrons pass from iodide ions to copper(II) ions.
- 4
In the reaction of copper(II) with iodide, four iodide ions react but only two are oxidised. Explain.
Model answer
Two of the iodide ions give up their electrons and combine to form one iodine molecule. The other two are not oxidised at all; they remain as iodide and combine with the copper(I) ions produced to precipitate two formula units of copper(I) iodide.
- 5
In what two ways does the iodide ion act in its reaction with copper(II) ions?
Model answer
It acts as a reducing agent, supplying the electrons that reduce copper(II) to copper(I). It also acts as a precipitating agent, removing the copper(I) formed as insoluble copper(I) iodide.
- 6
The standard electrode potential of Cu²⁺/Cu⁺ is +0.15 V and that of I₂/I⁻ is +0.54 V. Explain how copper(II) can nevertheless oxidise iodide ions.
Model answer
Comparing the two standard values suggests the reaction should not occur, since it would give a negative EMF. However the copper(I) formed is immediately removed from solution as insoluble copper(I) iodide, so the concentration of Cu⁺ is kept extremely low. That is a long way from standard conditions, and it shifts the copper electrode equilibrium so far to the right that the reaction becomes feasible.
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