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Redox Reactions

Combining half-equations into full equations

  • 3 things to know
  • A2 Unit 3

Overview

Fifteen recall questions on combining half-equations into full equations.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

Combine the dichromate(VI) half-equation with the oxidation of iron(II).

Key term

What is the overall equation for the reaction of acidified dichromate(VI) with iodide ions?

Key term

What is the overall equation for the reaction of acidified manganate(VII) with iodide ions?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How are two half-equations combined into an overall redox equation?

    Model answer

    Multiply each half-equation by whatever whole number is needed so that the number of electrons released by the oxidation equals the number taken up by the reduction. Add the two equations together, cancel the electrons, and cancel any water molecules or hydrogen ions that appear on both sides.

  2. 2

    Combine MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O with Fe²⁺ → Fe³⁺ + e⁻.

    Model answer

    Multiply the iron half-equation by five so five electrons are released, then add: MnO₄⁻ + 5Fe²⁺ + 8H⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O. The charge is −1 + 10 + 8 = +17 on the left and +2 + 15 = +17 on the right.

  3. 3

    Combine the dichromate(VI) half-equation with the oxidation of iron(II).

    Model answer

    Six electrons are gained by each dichromate ion, so multiply the iron half-equation by six: Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ → 2Cr³⁺ + 6Fe³⁺ + 7H₂O. The charge is −2 + 12 + 14 = +24 on the left and +6 + 18 = +24 on the right.

  4. 4

    What is the overall equation for the oxidation of ethanedioate ions by acidified manganate(VII)?

    Model answer

    Multiply the manganate(VII) half-equation by two and the ethanedioate half-equation by five so that ten electrons are transferred: 2MnO₄⁻ + 5C₂O₄²⁻ + 16H⁺ → 2Mn²⁺ + 10CO₂ + 8H₂O. The charge is −2 − 10 + 16 = +4 on both sides.

  5. 5

    What is the overall equation for the reaction of acidified manganate(VII) with hydrogen peroxide?

    Model answer

    2MnO₄⁻ + 5H₂O₂ + 6H⁺ → 2Mn²⁺ + 5O₂ + 8H₂O. Ten electrons are transferred, and the charge is −2 + 6 = +4 on the left and +4 on the right.

  6. 6

    What is the overall equation for the reaction of acidified dichromate(VI) with iodide ions?

    Model answer

    Cr₂O₇²⁻ + 6I⁻ + 14H⁺ → 2Cr³⁺ + 3I₂ + 7H₂O. Six electrons are transferred, and the charge is −2 − 6 + 14 = +6 on the left and +6 on the right.

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