WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Carboxylic Acids and Their Derivatives
Reduction and decarboxylation of carboxylic acids: reduction of carboxylic acids using LiAlH₄
- 3 things to know
- A2 Unit 4
Overview
Reducing carboxylic acids to primary alcohols with LiAlH₄ in dry ether, the equation using [H], why NaBH₄ cannot be used, and why the reduction cannot be stopped at the aldehyde.
What you need to know
Answer each one before you reveal it.
Why can NaBH₄ not be used in place of LiAlH₄ to reduce a carboxylic acid?
Can the reduction of a carboxylic acid be stopped at the aldehyde?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is formed when a carboxylic acid is reduced by lithium tetrahydridoaluminate(III)?
Model answer
A primary alcohol is formed. The carboxyl group is reduced all the way to a CH₂OH group and a molecule of water is lost.
- 2
Under what conditions is a reduction with LiAlH₄ carried out?
Model answer
The reagent is used in a dry ether solvent such as ethoxyethane at room temperature, with the apparatus kept free of moisture. The mixture is then treated with dilute acid in a separate work-up step to release the alcohol.
- 3
Why must the solvent for a LiAlH₄ reduction be dry?
Model answer
Lithium tetrahydridoaluminate(III) reacts violently with water, giving hydrogen gas and destroying the reagent before it can reduce the organic compound. A dry ether dissolves the reagent without reacting with it.
- 4
Write an equation, using [H], for the reduction of ethanoic acid.
Model answer
The equation is CH₃COOH + 4[H] → CH₃CH₂OH + H₂O. Four hydrogen atoms are needed because the reduction removes one of the oxygen atoms altogether.
- 5
Name the product formed when propanoic acid is treated with LiAlH₄ in dry ether and the mixture is then acidified.
Model answer
Propan-1-ol is formed. The carboxyl carbon becomes the carbon bearing the hydroxyl group, so the number of carbon atoms is unchanged.
- 6
Why can NaBH₄ not be used in place of LiAlH₄ to reduce a carboxylic acid?
Model answer
Sodium tetrahydridoborate(III) is a much milder reducing agent and can only reduce the strongly polarised carbonyl group of an aldehyde or ketone. The carbonyl carbon of a carboxylic acid is made less electron-deficient by the neighbouring hydroxyl oxygen, so it needs the far more powerful lithium tetrahydridoaluminate(III).
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