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Basic Ideas About Atoms

Atomic spectra and the energy of light: relationship between energy and frequency

  • 3 things to know
  • AS Unit 1

Overview

Recall questions on relationship between energy and frequency.

What you need to know

Answer each one before you reveal it.

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Key term

How are the frequency and wavelength of electromagnetic radiation related?

Key term

An electron transition in one atom releases an infrared photon and a transition in another releases an ultraviolet photon. Compare the energy gaps involved.

Key term

Why can ultraviolet radiation break covalent bonds when visible light of the same intensity usually cannot?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Write down the relationship between the energy of a photon and its frequency, naming every symbol.

    Model answer

    E = hf, where E is the energy of one photon in joules, f is its frequency in hertz and h is the Planck constant, 6.63 × 10⁻³⁴ J s.

  2. 2

    How are the frequency and wavelength of electromagnetic radiation related?

    Model answer

    By f = c/λ, where f is the frequency in hertz, λ is the wavelength in metres and c is the speed of light, 3.00 × 10⁸ m s⁻¹. Frequency and wavelength are inversely proportional, so a shorter wavelength means a higher frequency.

  3. 3

    Combine the two relationships to give an expression for photon energy in terms of wavelength.

    Model answer

    Substituting f = c/λ into E = hf gives E = hc/λ. Photon energy is therefore inversely proportional to wavelength, so short-wavelength radiation carries the more energetic photons.

  4. 4

    Calculate the energy of a photon of frequency 4.57 × 10¹⁴ Hz.

    Model answer

    E = hf = 6.63 × 10⁻³⁴ J s × 4.57 × 10¹⁴ s⁻¹ = 3.03 × 10⁻¹⁹ J. The data are given to three significant figures, so the answer is quoted to three.

  5. 5

    A line in the hydrogen spectrum has a wavelength of 486 nm. Find its frequency.

    Model answer

    First convert to metres: 486 nm = 4.86 × 10⁻⁷ m. Then f = c/λ = (3.00 × 10⁸ m s⁻¹) ÷ (4.86 × 10⁻⁷ m) = 6.17 × 10¹⁴ Hz, to three significant figures.

  6. 6

    Calculate the energy of a photon of wavelength 486 nm.

    Model answer

    E = hc/λ = (6.63 × 10⁻³⁴ J s × 3.00 × 10⁸ m s⁻¹) ÷ (4.86 × 10⁻⁷ m) = (1.99 × 10⁻²⁵ J m) ÷ (4.86 × 10⁻⁷ m) = 4.09 × 10⁻¹⁹ J.

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