WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Basic Ideas About Atoms
Atomic spectra and the energy of light: relationship between energy and frequency
- 3 things to know
- AS Unit 1
Overview
Recall questions on relationship between energy and frequency.
What you need to know
Answer each one before you reveal it.
An electron transition in one atom releases an infrared photon and a transition in another releases an ultraviolet photon. Compare the energy gaps involved.
Why can ultraviolet radiation break covalent bonds when visible light of the same intensity usually cannot?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write down the relationship between the energy of a photon and its frequency, naming every symbol.
Model answer
E = hf, where E is the energy of one photon in joules, f is its frequency in hertz and h is the Planck constant, 6.63 × 10⁻³⁴ J s.
- 2
How are the frequency and wavelength of electromagnetic radiation related?
Model answer
By f = c/λ, where f is the frequency in hertz, λ is the wavelength in metres and c is the speed of light, 3.00 × 10⁸ m s⁻¹. Frequency and wavelength are inversely proportional, so a shorter wavelength means a higher frequency.
- 3
Combine the two relationships to give an expression for photon energy in terms of wavelength.
Model answer
Substituting f = c/λ into E = hf gives E = hc/λ. Photon energy is therefore inversely proportional to wavelength, so short-wavelength radiation carries the more energetic photons.
- 4
Calculate the energy of a photon of frequency 4.57 × 10¹⁴ Hz.
Model answer
E = hf = 6.63 × 10⁻³⁴ J s × 4.57 × 10¹⁴ s⁻¹ = 3.03 × 10⁻¹⁹ J. The data are given to three significant figures, so the answer is quoted to three.
- 5
A line in the hydrogen spectrum has a wavelength of 486 nm. Find its frequency.
Model answer
First convert to metres: 486 nm = 4.86 × 10⁻⁷ m. Then f = c/λ = (3.00 × 10⁸ m s⁻¹) ÷ (4.86 × 10⁻⁷ m) = 6.17 × 10¹⁴ Hz, to three significant figures.
- 6
Calculate the energy of a photon of wavelength 486 nm.
Model answer
E = hc/λ = (6.63 × 10⁻³⁴ J s × 3.00 × 10⁸ m s⁻¹) ÷ (4.86 × 10⁻⁷ m) = (1.99 × 10⁻²⁵ J m) ÷ (4.86 × 10⁻⁷ m) = 4.09 × 10⁻¹⁹ J.
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