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The Periodic Table

Oxidation and reduction as electron transfer

  • 3 things to know
  • AS Unit 1

Overview

Recall questions on disproportionation.

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Numbers

In the reaction between magnesium and chlorine, which element is oxidised and which is reduced?

Key term

Write half equations for the oxidation and the reduction taking place when calcium burns in oxygen.

Key term

Oxygen is usually assigned an oxidation number of −2, but not in hydrogen peroxide. What is it there, and why?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Define oxidation and reduction in terms of electrons.

    Model answer

    Oxidation is the loss of electrons by a species and reduction is the gain of electrons. In terms of oxidation number, oxidation is an increase and reduction is a decrease.

  2. 2

    In the reaction between magnesium and chlorine, which element is oxidised and which is reduced?

    Model answer

    Magnesium is oxidised because each atom loses two electrons to become Mg²⁺, its oxidation number rising from 0 to +2. Chlorine is reduced because each atom gains one electron to become Cl⁻, its oxidation number falling from 0 to −1. The overall equation is Mg + Cl₂ → MgCl₂.

  3. 3

    Write half equations for the oxidation and the reduction taking place when calcium burns in oxygen.

    Model answer

    Oxidation: Ca → Ca²⁺ + 2e⁻. Reduction: O₂ + 4e⁻ → 2O²⁻. Two calcium atoms are needed for each oxygen molecule, giving 2Ca + O₂ → 2CaO.

  4. 4

    What is an oxidising agent, and what happens to it during a reaction?

    Model answer

    An oxidising agent is a species that removes electrons from something else, causing it to be oxidised. In doing so the oxidising agent itself gains those electrons and is reduced.

  5. 5

    Deduce the oxidation number of manganese in the manganate(VII) ion, MnO₄⁻.

    Model answer

    Each oxygen is −2, giving −8 in total, and the overall charge is −1. The manganese oxidation number must therefore be −1 minus −8, which is +7.

  6. 6

    Work out the oxidation number of chromium in the dichromate(VI) ion, Cr₂O₇²⁻.

    Model answer

    Seven oxygens at −2 give −14, and the overall charge is −2. The two chromium atoms must therefore total +12, so each chromium is +6.

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