WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
The Periodic Table
Oxidation and reduction as electron transfer
- 3 things to know
- AS Unit 1
Overview
Recall questions on disproportionation.
What you need to know
Answer each one before you reveal it.
Write half equations for the oxidation and the reduction taking place when calcium burns in oxygen.
Oxygen is usually assigned an oxidation number of −2, but not in hydrogen peroxide. What is it there, and why?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define oxidation and reduction in terms of electrons.
Model answer
Oxidation is the loss of electrons by a species and reduction is the gain of electrons. In terms of oxidation number, oxidation is an increase and reduction is a decrease.
- 2
In the reaction between magnesium and chlorine, which element is oxidised and which is reduced?
Model answer
Magnesium is oxidised because each atom loses two electrons to become Mg²⁺, its oxidation number rising from 0 to +2. Chlorine is reduced because each atom gains one electron to become Cl⁻, its oxidation number falling from 0 to −1. The overall equation is Mg + Cl₂ → MgCl₂.
- 3
Write half equations for the oxidation and the reduction taking place when calcium burns in oxygen.
Model answer
Oxidation: Ca → Ca²⁺ + 2e⁻. Reduction: O₂ + 4e⁻ → 2O²⁻. Two calcium atoms are needed for each oxygen molecule, giving 2Ca + O₂ → 2CaO.
- 4
What is an oxidising agent, and what happens to it during a reaction?
Model answer
An oxidising agent is a species that removes electrons from something else, causing it to be oxidised. In doing so the oxidising agent itself gains those electrons and is reduced.
- 5
Deduce the oxidation number of manganese in the manganate(VII) ion, MnO₄⁻.
Model answer
Each oxygen is −2, giving −8 in total, and the overall charge is −1. The manganese oxidation number must therefore be −1 minus −8, which is +7.
- 6
Work out the oxidation number of chromium in the dichromate(VI) ion, Cr₂O₇²⁻.
Model answer
Seven oxygens at −2 give −14, and the overall charge is −2. The two chromium atoms must therefore total +12, so each chromium is +6.
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