WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemical Calculations
Empirical and molecular formulae
- 3 things to know
- AS Unit 1
Overview
Recall questions on Empirical formulae and molecular formulae.
What you need to know
Answer each one before you reveal it.
Heating 2.8 g of iron in oxygen produces 4.0 g of an oxide. Work out the empirical formula of the oxide.
Why does an empirical formula calculation often give a ratio like 1 : 1.5 rather than whole numbers, and what should you do?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the difference between an empirical formula and a molecular formula?
Model answer
An empirical formula gives the simplest whole-number ratio of the atoms of each element present. A molecular formula gives the actual number of atoms of each element in one molecule, and is always a whole-number multiple of the empirical formula.
- 2
Give the empirical formulae of ethane, C₂H₆, and of benzene, C₆H₆.
Model answer
Ethane has a carbon-to-hydrogen ratio of 2 : 6, which simplifies to 1 : 3, so its empirical formula is CH₃. Benzene has a ratio of 6 : 6, which simplifies to 1 : 1, so its empirical formula is CH.
- 3
Why can two different compounds share the same empirical formula?
Model answer
The empirical formula records only the ratio of the atoms, not how many there are or how they are joined. Ethene, C₂H₄, and butene, C₄H₈, both reduce to CH₂, yet they are different substances with different molecular formulae.
- 4
Outline the steps for finding an empirical formula from percentage composition by mass.
Model answer
Treat the percentages as masses in grams for a 100 g sample, divide each by the relative atomic mass of that element to get the amount in moles, divide all the results by the smallest of them, and then multiply through if needed to reach whole numbers.
- 5
A compound is 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Determine its empirical formula.
Model answer
In 100 g there are 40.0 ÷ 12.0 = 3.33 mol C, 6.7 ÷ 1.0 = 6.7 mol H and 53.3 ÷ 16.0 = 3.33 mol O. Dividing by the smallest, 3.33, gives 1.00 : 2.01 : 1.00, so the empirical formula is CH₂O.
- 6
A compound with the empirical formula CH₂O has a relative molecular mass of 180. What is its molecular formula?
Model answer
The empirical formula mass is 12.0 + 2.0 + 16.0 = 30.0. Dividing gives 180 ÷ 30.0 = 6, so every subscript is multiplied by six and the molecular formula is C₆H₁₂O₆.
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