WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Simple Equilibria and Acid-Base Reactions
Le Chatelier's principle and shifting the position of equilibrium
- 3 things to know
- AS Unit 1
Overview
Seventeen recall questions on Le Chatelier's principle and shifting the position of equilibrium.
What you need to know
Answer each one before you reveal it.
State Le Chatelier's principle.
What effect does adding a catalyst have on the position of an equilibrium?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State Le Chatelier's principle.
Model answer
Le Chatelier's principle states that if a system at equilibrium is subjected to a change in conditions, the position of equilibrium moves in the direction that tends to reduce the effect of that change.
- 2
For the equilibrium H₂(g) + I₂(g) ⇌ 2HI(g), predict and explain the effect of adding more iodine at constant temperature.
Model answer
The position of equilibrium shifts to the right. Adding iodine raises its concentration, so the system responds by removing iodine; more hydrogen iodide is formed and the concentration of hydrogen falls.
- 3
In the equilibrium CH₃COOH(l) + C₂H₅OH(l) ⇌ CH₃COOC₂H₅(l) + H₂O(l), what happens to the yield of ester if water is continually removed?
Model answer
The yield of ester increases. Removing water lowers its concentration, so the equilibrium shifts to the right to replace it, converting more of the acid and alcohol into ester.
- 4
Why does increasing the total pressure on the equilibrium N₂(g) + 3H₂(g) ⇌ 2NH₃(g) increase the proportion of ammonia?
Model answer
There are four moles of gas on the left and only two on the right. Raising the pressure is opposed by a shift towards the side with fewer gas molecules, so the equilibrium moves to the right and the proportion of ammonia rises.
- 5
Why does a change in pressure have no effect on the position of the equilibrium H₂(g) + I₂(g) ⇌ 2HI(g)?
Model answer
There are two moles of gas on each side of the equation, so a shift in either direction would not change the total number of gas molecules and could not oppose the pressure change. The position of equilibrium is therefore unaffected.
- 6
State and explain the effect of raising the temperature on the equilibrium 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), for which ΔH = ‒196 kJ mol⁻¹.
Model answer
Raising the temperature shifts the equilibrium to the left. The forward reaction is exothermic, so the backward reaction is endothermic; the system opposes the temperature rise by favouring the direction that absorbs heat, and the yield of sulfur trioxide falls.
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