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Aromaticity

Electrophilic substitution: nitration, halogenation and alkylation

  • 3 things to know
  • A2 Unit 4

Overview

Recall questions on nitration, halogenation and alkylation.

What you need to know

Answer each one before you reveal it.

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Process

Describe the mechanism of the nitration of benzene.

Key term

Write equations for the alkylation of benzene by chloromethane, showing the electrophile.

Key term

Why can a Friedel-Crafts alkylation give a mixture containing polysubstituted products?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why does an electrophile attack the ring of methylbenzene rather than its methyl side chain?

    Model answer

    The delocalised π system of the ring is a region of high electron density that attracts an electron-pair acceptor, whereas the methyl group is a saturated alkyl group with no such region and no lone pair, so it offers the electrophile nothing to attack.

  2. 2

    Why is benzene attacked by electrophiles rather than by nucleophiles?

    Model answer

    The ring carries six delocalised pi electrons in clouds above and below its plane, so it is a region of high electron density. That attracts electron-deficient species, while nucleophiles, which are themselves electron rich, are repelled.

  3. 3

    Outline the general pattern of electrophilic substitution in benzene.

    Model answer

    The electrophile is attracted to the delocalised ring, and two of the pi electrons form a bond to it, giving a positively charged intermediate in which the delocalisation is broken and spread over only five carbons. A base then removes the hydrogen from the carbon that was attacked, and the electron pair from that bond returns to the ring, restoring the full delocalised system.

  4. 4

    Why is the intermediate formed during electrophilic substitution unstable?

    Model answer

    Forming the bond to the electrophile uses two of the six delocalised electrons, so the intermediate is left with only four spread over five carbon atoms and carries a positive charge. It has lost the aromatic stabilisation of the parent ring, so it is high in energy and reverts to an aromatic structure as fast as it can.

  5. 5

    Why does the intermediate lose a proton rather than gain a nucleophile?

    Model answer

    Losing the proton returns the electron pair to the ring and restores the delocalised system, recovering the aromatic stabilisation energy. Adding a nucleophile would give a saturated product with no aromatic ring, which is much higher in energy.

  6. 6

    State the reagents and conditions for the nitration of benzene.

    Model answer

    Concentrated nitric acid with concentrated sulfuric acid as catalyst, warmed under reflux to about 50 to 55 °C. Keeping the temperature below about 55 °C limits the reaction to a single substitution, since a hotter mixture goes on to give dinitrobenzene.

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