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Chemistry of the P-Block

Group 4 oxides and chlorides, and lead in solution: distinguishing lead from silver ions

  • 3 things to know
  • A2 Unit 3

Overview

Eleven recall questions on group 4 oxides and chlorides, and lead in solution: distinguishing lead from silver ions.

What you need to know

Answer each one before you reveal it.

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Key term

Explain how you could use sodium hydroxide solution and potassium iodide solution together to confirm the presence of lead(II) ions in a colourless solution.

Key term

A student adds sodium hydroxide solution slowly to a lead(II) salt solution and reports no precipitate at all. Suggest what went wrong.

Key term

Both the chloride and the iodide of lead(II) are insoluble. Why does the colour of the precipitate differ so markedly?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe what happens when the yellow precipitate formed from lead(II) ions and iodide ions is heated with water and then allowed to cool slowly.

    Model answer

    The precipitate dissolves in the hot water to give a colourless solution, and on slow cooling lead(II) iodide crystallises out as glittering golden-yellow plates. The effect is often called a shower of gold.

  2. 2

    Explain how you could use sodium hydroxide solution and potassium iodide solution together to confirm the presence of lead(II) ions in a colourless solution.

    Model answer

    Sodium hydroxide gives a white precipitate that dissolves in excess to a colourless solution, showing an amphoteric hydroxide. Potassium iodide then gives a bright yellow precipitate, which among the common cations is characteristic of lead(II). The two results together confirm Pb²⁺.

  3. 3

    Lead(II) chloride dissolves when concentrated hydrochloric acid is added. Explain why, and name the species formed.

    Model answer

    A high concentration of chloride ions converts the insoluble chloride into a soluble complex ion, PbCl₂(s) + 2Cl⁻(aq) → [PbCl₄]²⁻(aq). The species formed is the tetrachloroplumbate(II) ion, and the solution becomes colourless and clear.

  4. 4

    Why should chloride ions be avoided when preparing a solution of a lead(II) salt?

    Model answer

    Lead(II) chloride is only sparingly soluble in cold water, so chloride ions precipitate the lead out of solution as a white solid. A nitrate, which is soluble, should be used instead.

  5. 5

    Silver ions also give a white precipitate with chloride ions and a yellow precipitate with iodide ions. How could you distinguish silver(I) from lead(II) using aqueous ammonia?

    Model answer

    Silver chloride dissolves in dilute aqueous ammonia to give a colourless solution of the diamminesilver(I) ion, whereas lead(II) chloride does not dissolve in ammonia. The precipitate that dissolves therefore contains silver.

  6. 6

    A student adds sodium hydroxide solution slowly to a lead(II) salt solution and reports no precipitate at all. Suggest what went wrong.

    Model answer

    Probably too much alkali was added in total before looking, or the mixture was not shaken, so the lead(II) hydroxide redissolved in the excess to give the colourless plumbate(II) ion. The alkali must be added dropwise with shaking, watching after each drop for the white precipitate.

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