WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Practical Skills and Techniques
Electrochemical cells, rate methods and working safely: rate methods and working safely
- 3 things to know
- All units
Overview
Recall questions on rate methods and working safely.
What you need to know
Answer each one before you reveal it.
Explain the principle of an iodine clock reaction.
Why is the reciprocal of the time in an iodine clock reaction taken as a measure of the initial rate?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe the apparatus used to follow the rate of a reaction that produces a gas by measuring gas volume.
Model answer
The reactants are mixed in a conical flask fitted with a bung carrying a delivery tube leading to a gas syringe, and the clock is started as the reagents are mixed. The volume of gas is recorded at fixed time intervals and plotted against time.
- 2
Why must the bung be fitted to the flask immediately after mixing in a gas collection experiment?
Model answer
The reaction is fastest at the start, so gas is produced rapidly in the first few seconds. Any delay lets that gas escape, giving volumes that are too small and an initial rate that is too low.
- 3
Before a rate experiment, why is the gas syringe plunger checked to make sure it slides freely, and what error arises if it sticks?
Model answer
A stiff or dirty plunger only moves once the pressure in the flask has built up, so the syringe reads too low at first and then jumps forward. The early points of the volume–time graph are therefore wrong, and it is exactly there that the tangent for the initial rate is drawn, so the rate would come out too small. Pushing the plunger in and letting it slide back before the experiment shows whether it moves freely.
- 4
A tangent drawn at the start of a volume-time graph passes through the origin and the point (30 s, 24.0 cm³). Calculate the initial rate in cm³ s⁻¹, and in mol s⁻¹ if the molar volume of the gas is 24.0 dm³ mol⁻¹.
Model answer
Initial rate = 24.0 / 30 = 0.80 cm³ s⁻¹. Converting, 0.80 cm³ s⁻¹ = 8.0 × 10⁻⁴ dm³ s⁻¹, so the rate = 8.0 × 10⁻⁴ / 24.0 = 3.3 × 10⁻⁵ mol s⁻¹.
- 5
Explain the principle of an iodine clock reaction.
Model answer
Iodine is generated steadily by the reaction under study, but a small, fixed amount of sodium thiosulfate present in the mixture immediately reduces it back to iodide. Once the thiosulfate has all been used up, free iodine accumulates and gives a sudden blue-black colour with the starch present, and the time taken for this to appear is measured.
- 6
Why is the reciprocal of the time in an iodine clock reaction taken as a measure of the initial rate?
Model answer
The same small amount of iodine has been produced in every run by the time the colour appears, so the amount of reaction that has occurred is fixed. Rate is amount of change divided by time, so with the amount constant the rate is proportional to 1/t.
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