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Practical Skills and Techniques

Electrochemical cells, rate methods and working safely: rate methods and working safely

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Overview

Recall questions on rate methods and working safely.

What you need to know

Answer each one before you reveal it.

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Key term

Describe the apparatus used to follow the rate of a reaction that produces a gas by measuring gas volume.

Key term

Explain the principle of an iodine clock reaction.

Numbers

Why is the reciprocal of the time in an iodine clock reaction taken as a measure of the initial rate?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the apparatus used to follow the rate of a reaction that produces a gas by measuring gas volume.

    Model answer

    The reactants are mixed in a conical flask fitted with a bung carrying a delivery tube leading to a gas syringe, and the clock is started as the reagents are mixed. The volume of gas is recorded at fixed time intervals and plotted against time.

  2. 2

    Why must the bung be fitted to the flask immediately after mixing in a gas collection experiment?

    Model answer

    The reaction is fastest at the start, so gas is produced rapidly in the first few seconds. Any delay lets that gas escape, giving volumes that are too small and an initial rate that is too low.

  3. 3

    Before a rate experiment, why is the gas syringe plunger checked to make sure it slides freely, and what error arises if it sticks?

    Model answer

    A stiff or dirty plunger only moves once the pressure in the flask has built up, so the syringe reads too low at first and then jumps forward. The early points of the volume–time graph are therefore wrong, and it is exactly there that the tangent for the initial rate is drawn, so the rate would come out too small. Pushing the plunger in and letting it slide back before the experiment shows whether it moves freely.

  4. 4

    A tangent drawn at the start of a volume-time graph passes through the origin and the point (30 s, 24.0 cm³). Calculate the initial rate in cm³ s⁻¹, and in mol s⁻¹ if the molar volume of the gas is 24.0 dm³ mol⁻¹.

    Model answer

    Initial rate = 24.0 / 30 = 0.80 cm³ s⁻¹. Converting, 0.80 cm³ s⁻¹ = 8.0 × 10⁻⁴ dm³ s⁻¹, so the rate = 8.0 × 10⁻⁴ / 24.0 = 3.3 × 10⁻⁵ mol s⁻¹.

  5. 5

    Explain the principle of an iodine clock reaction.

    Model answer

    Iodine is generated steadily by the reaction under study, but a small, fixed amount of sodium thiosulfate present in the mixture immediately reduces it back to iodide. Once the thiosulfate has all been used up, free iodine accumulates and gives a sudden blue-black colour with the starch present, and the time taken for this to appear is measured.

  6. 6

    Why is the reciprocal of the time in an iodine clock reaction taken as a measure of the initial rate?

    Model answer

    The same small amount of iodine has been produced in every run by the time the colour appears, so the amount of reaction that has occurred is fixed. Rate is amount of change divided by time, so with the amount constant the rate is proportional to 1/t.

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