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Hydrocarbons

Alkane bonding, combustion and fossil fuels: combustion calculations and acid rain

  • 2 things to know
  • AS Unit 2

Overview

Calculating the volumes and masses of gases in alkane combustion, sulfur in fuels and acid rain, complete and incomplete combustion, and why alkanes are unreactive but make good fuels.

What you need to know

Answer each one before you reveal it.

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Key term

Why does acid rain damage limestone buildings?

Key term

Why is a blue flame on a gas burner a sign of better combustion than a yellow one?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What volume of oxygen, measured at room temperature and pressure, is needed for the complete combustion of 2.40 dm³ of propane measured under the same conditions?

    Model answer

    The equation C₃H₈ + 5O₂ → 3CO₂ + 4H₂O shows that 1 mol of propane needs 5 mol of oxygen, and for gases at the same temperature and pressure the volumes are in the same ratio as the moles, so the volume required is 5 × 2.40 dm³ = 12.0 dm³.

  2. 2

    Calculate the mass of carbon dioxide released when 1.00 kg of octane, C₈H₁₈, burns completely. (Ar: C = 12.0, H = 1.0, O = 16.0)

    Model answer

    The molar mass of octane is (8 × 12.0) + (18 × 1.0) = 114.0 g mol⁻¹, so 1000 g is 1000 ÷ 114.0 = 8.772 mol. Each mole of octane gives 8 mol of carbon dioxide, so 70.18 mol of CO₂ is formed, and its mass is 70.18 × 44.0 = 3088 g, which is 3.09 kg to three significant figures.

  3. 3

    Calculate the mass of water formed when 5.80 g of butane burns completely. (Ar: C = 12.0, H = 1.0, O = 16.0)

    Model answer

    The molar mass of butane is (4 × 12.0) + (10 × 1.0) = 58.0 g mol⁻¹, so 5.80 g is 0.100 mol. The equation 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O gives 5 mol of water per mole of butane, so 0.500 mol of water is formed, and its mass is 0.500 × 18.0 = 9.00 g.

  4. 4

    A heavy fuel oil contains 1.20% sulfur by mass. Calculate the mass of sulfur dioxide released when 1.00 tonne of the oil is burned. (Ar: S = 32.1, O = 16.0)

    Model answer

    One tonne is 1.00 × 10⁶ g, so the mass of sulfur is 0.0120 × 1.00 × 10⁶ = 1.20 × 10⁴ g. That is 1.20 × 10⁴ ÷ 32.1 = 373.8 mol of sulfur, and since S + O₂ → SO₂ the same number of moles of sulfur dioxide is formed. Its molar mass is 32.1 + (2 × 16.0) = 64.1 g mol⁻¹, so the mass released is 373.8 × 64.1 = 2.40 × 10⁴ g, or 24.0 kg.

  5. 5

    Why is a blue flame on a gas burner a sign of better combustion than a yellow one?

    Model answer

    A yellow flame is coloured by glowing particles of carbon produced because there is not enough oxygen reaching the flame, whereas a blue flame shows the fuel is burning completely, releasing more energy per mole and producing no soot or carbon monoxide.

  6. 6

    Why are alkanes so unreactive towards acids, alkalis and other polar reagents?

    Model answer

    Alkanes contain only strong C–C and C–H σ-bonds, and because carbon and hydrogen have very similar electronegativities those bonds are essentially non-polar, so there is no site of high or low electron density for a nucleophile or an electrophile to attack.

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