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Alcohols and Phenols

Making primary and secondary alcohols

  • 3 things to know
  • A2 Unit 4

Overview

Recall questions on Making primary and secondary alcohols.

What you need to know

Answer each one before you reveal it.

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Numbers

Name the alcohols formed when propanone and butanone are reduced, and describe how the hydride reagent attacks a carbonyl group.

Key term

Suggest why reduction of a ketone can never give a primary alcohol.

Key term

Why does hydrolysing a halogenoalkane with water alone work poorly compared with using aqueous sodium hydroxide?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What distinguishes a primary, a secondary and a tertiary alcohol?

    Model answer

    The classification depends on how many carbon atoms are attached to the carbon bearing the hydroxyl group. In a primary alcohol that carbon carries one other carbon at most, in a secondary alcohol two, and in a tertiary alcohol three.

  2. 2

    How is an alcohol made from a halogenoalkane?

    Model answer

    The halogenoalkane is heated under reflux with aqueous sodium hydroxide. The hydroxide ion acts as a nucleophile and displaces the halogen as a halide ion, replacing it with a hydroxyl group in a nucleophilic substitution.

  3. 3

    Write the equation for the reaction of 1-bromopropane with aqueous sodium hydroxide and name the product.

    Model answer

    CH₃CH₂CH₂Br + NaOH → CH₃CH₂CH₂OH + NaBr. The product is propan-1-ol, a primary alcohol, because the bromine was on a carbon at the end of the chain.

  4. 4

    What alcohol is formed when 2-bromopropane is refluxed with aqueous sodium hydroxide?

    Model answer

    Propan-2-ol, a secondary alcohol, since the hydroxyl group takes the place of the bromine on the middle carbon. The equation is CH₃CHBrCH₃ + NaOH → CH₃CH(OH)CH₃ + NaBr.

  5. 5

    Why is the sodium hydroxide used aqueous rather than dissolved in ethanol when an alcohol is wanted?

    Model answer

    In aqueous solution the hydroxide ion acts mainly as a nucleophile and attacks the carbon, giving substitution and therefore the alcohol. In ethanolic solution it behaves mainly as a base and removes a hydrogen from the neighbouring carbon, giving elimination and an alkene instead.

  6. 6

    Why is the mixture heated under reflux rather than simply heated in an open flask?

    Model answer

    Heating raises the rate so the substitution completes in a reasonable time, but both the halogenoalkane and the alcohol are volatile and would be lost as vapour. The reflux condenser returns the vapour to the flask, so nothing escapes while the mixture is held at its boiling temperature.

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