WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Organic Synthesis and Analysis
Polymers: hydrolysis, properties and identifying repeat units
- 3 things to know
- A2 Unit 4
Overview
Why polyesters and polyamides can be hydrolysed while addition polymers resist attack, the products of hydrolysis, melting points, and identifying the monomers and repeat unit from a section of chain.
What you need to know
Answer each one before you reveal it.
What products are formed when a polyester is heated with hot aqueous sodium hydroxide?
Why do polyamides generally melt at higher temperatures than polyesters with chains of comparable length?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is poly(ethene) not attacked by acids or alkalis, whereas a polyester is slowly broken down by them?
Model answer
The backbone of poly(ethene) is a chain of carbon atoms joined by non-polar C−C and C−H bonds, which are strong and offer no site for a nucleophile or an electrophile to attack. A polyester backbone contains ester links whose carbonyl carbon is δ+ because of the two electronegative oxygen atoms. This carbon is open to attack by water or hydroxide, so the ester links can be hydrolysed and the chain broken.
- 2
What products are formed when a polyamide is heated with hot aqueous hydrochloric acid?
Model answer
The amide links are hydrolysed, breaking the chain into its monomer units. The dicarboxylic acid is released as the free acid, but the diamine is protonated by the excess acid and is obtained as its ammonium salt, for example ⁺H₃N(CH₂)₆NH₃⁺ with chloride ions. Adding alkali afterwards would release the free diamine.
- 3
What products are formed when a polyester is heated with hot aqueous sodium hydroxide?
Model answer
The ester links are hydrolysed, breaking the chain. The diol is released as the free alcohol, and the dicarboxylic acid is obtained as its sodium salt, the dicarboxylate, because the alkali is in excess. Acidifying the mixture afterwards would give back the free dicarboxylic acid.
- 4
Why do polyamides generally melt at higher temperatures than polyesters with chains of comparable length?
Model answer
The amide link contains an N−H group, whose hydrogen is δ+, as well as a C=O whose oxygen carries lone pairs, so neighbouring polyamide chains can hydrogen bond strongly to one another. An ester link has a C=O that can accept a hydrogen bond but has no hydrogen attached to an electronegative atom, so ester chains cannot hydrogen bond to each other and are held only by weaker dipole–dipole attractions and van der Waals forces. More energy is therefore needed to separate polyamide chains.
- 5
A section of a polymer chain is −CH₂−CH(CN)−CH₂−CH(CN)−CH₂−CH(CN)−. Say which kind of polymerisation formed it and identify the monomer.
Model answer
The backbone is an unbroken chain of carbon atoms with no ester or amide links, and the repeat unit −CH₂−CH(CN)− contains the same atoms as a small unsaturated molecule, so it was formed by addition polymerisation. The monomer is CH₂=CHCN, propenenitrile.
- 6
A section of a polymer chain is −CO−(CH₂)₈−CO−O−CH₂CH₂−O−. Identify the type of polymer and its monomers.
Model answer
The chain contains −CO−O− ester links, so it is a polyester made by condensation polymerisation. Splitting each ester link by adding water across it, with the −OH going to the carbonyl carbon, gives the dicarboxylic acid HOOC(CH₂)₈COOH, decanedioic acid, and the diol HOCH₂CH₂OH, ethane-1,2-diol.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Organic Synthesis and Analysis, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.