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Organic Synthesis and Analysis

Polymers: hydrolysis, properties and identifying repeat units

  • 3 things to know
  • A2 Unit 4

Overview

Why polyesters and polyamides can be hydrolysed while addition polymers resist attack, the products of hydrolysis, melting points, and identifying the monomers and repeat unit from a section of chain.

What you need to know

Answer each one before you reveal it.

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Key term

What products are formed when a polyamide is heated with hot aqueous hydrochloric acid?

Key term

What products are formed when a polyester is heated with hot aqueous sodium hydroxide?

Numbers

Why do polyamides generally melt at higher temperatures than polyesters with chains of comparable length?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why is poly(ethene) not attacked by acids or alkalis, whereas a polyester is slowly broken down by them?

    Model answer

    The backbone of poly(ethene) is a chain of carbon atoms joined by non-polar C−C and C−H bonds, which are strong and offer no site for a nucleophile or an electrophile to attack. A polyester backbone contains ester links whose carbonyl carbon is δ+ because of the two electronegative oxygen atoms. This carbon is open to attack by water or hydroxide, so the ester links can be hydrolysed and the chain broken.

  2. 2

    What products are formed when a polyamide is heated with hot aqueous hydrochloric acid?

    Model answer

    The amide links are hydrolysed, breaking the chain into its monomer units. The dicarboxylic acid is released as the free acid, but the diamine is protonated by the excess acid and is obtained as its ammonium salt, for example ⁺H₃N(CH₂)₆NH₃⁺ with chloride ions. Adding alkali afterwards would release the free diamine.

  3. 3

    What products are formed when a polyester is heated with hot aqueous sodium hydroxide?

    Model answer

    The ester links are hydrolysed, breaking the chain. The diol is released as the free alcohol, and the dicarboxylic acid is obtained as its sodium salt, the dicarboxylate, because the alkali is in excess. Acidifying the mixture afterwards would give back the free dicarboxylic acid.

  4. 4

    Why do polyamides generally melt at higher temperatures than polyesters with chains of comparable length?

    Model answer

    The amide link contains an N−H group, whose hydrogen is δ+, as well as a C=O whose oxygen carries lone pairs, so neighbouring polyamide chains can hydrogen bond strongly to one another. An ester link has a C=O that can accept a hydrogen bond but has no hydrogen attached to an electronegative atom, so ester chains cannot hydrogen bond to each other and are held only by weaker dipole–dipole attractions and van der Waals forces. More energy is therefore needed to separate polyamide chains.

  5. 5

    A section of a polymer chain is −CH₂−CH(CN)−CH₂−CH(CN)−CH₂−CH(CN)−. Say which kind of polymerisation formed it and identify the monomer.

    Model answer

    The backbone is an unbroken chain of carbon atoms with no ester or amide links, and the repeat unit −CH₂−CH(CN)− contains the same atoms as a small unsaturated molecule, so it was formed by addition polymerisation. The monomer is CH₂=CHCN, propenenitrile.

  6. 6

    A section of a polymer chain is −CO−(CH₂)₈−CO−O−CH₂CH₂−O−. Identify the type of polymer and its monomers.

    Model answer

    The chain contains −CO−O− ester links, so it is a polyester made by condensation polymerisation. Splitting each ester link by adding water across it, with the −OH going to the carbonyl carbon, gives the dicarboxylic acid HOOC(CH₂)₈COOH, decanedioic acid, and the diol HOCH₂CH₂OH, ethane-1,2-diol.

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