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Carboxylic Acids and Their Derivatives

Making carboxylic acids by oxidation

  • 3 things to know
  • A2 Unit 4

Overview

24 recall questions on making carboxylic acids by oxidation.

What you need to know

Answer each one before you reveal it.

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Key term

What reagents and conditions convert a primary alcohol all the way to a carboxylic acid?

Numbers

Why is the mixture heated under reflux rather than distilled straight away when a carboxylic acid is wanted?

Numbers

Give the full ionic equation for the oxidation of ethanal by acidified dichromate(VI) ions.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What reagents and conditions convert a primary alcohol all the way to a carboxylic acid?

    Model answer

    The alcohol is heated under reflux with an excess of potassium dichromate(VI) acidified with dilute sulfuric acid. The reflux condenser returns any volatile aldehyde to the flask so that the oxidation is completed, and the acid is distilled off afterwards.

  2. 2

    Why is the mixture heated under reflux rather than distilled straight away when a carboxylic acid is wanted?

    Model answer

    The aldehyde formed first is volatile and would escape if the mixture were distilled immediately, stopping the oxidation half way. Refluxing condenses the aldehyde back into the flask so that it is oxidised on to the carboxylic acid.

  3. 3

    Write an equation, using [O], for the complete oxidation of ethanol to ethanoic acid.

    Model answer

    The equation is CH₃CH₂OH + 2[O] → CH₃COOH + H₂O. Two oxidation steps are involved, first to ethanal and then on to the acid.

  4. 4

    Give the full ionic equation for the oxidation of propan-1-ol to propanoic acid by acidified dichromate(VI) ions, and state the condition needed to obtain the acid rather than the aldehyde.

    Model answer

    The equation is 3CH₃CH₂CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃CH₂COOH + 4Cr³⁺ + 11H₂O. Each alcohol molecule loses four electrons and each dichromate(VI) ion gains six, so three alcohol molecules are matched with two dichromate(VI) ions. The mixture must be heated under reflux with excess oxidising agent, so that any propanal formed is returned to the flask and oxidised on to the acid.

  5. 5

    Write an equation, using [O], for the oxidation of propanal.

    Model answer

    The equation is CH₃CH₂CHO + [O] → CH₃CH₂COOH. Propanal is oxidised to propanoic acid, and unlike the oxidation of an alcohol no water is produced.

  6. 6

    Give the full ionic equation for the oxidation of ethanal by acidified dichromate(VI) ions.

    Model answer

    The equation is 3CH₃CHO + Cr₂O₇²⁻ + 8H⁺ → 3CH₃COOH + 2Cr³⁺ + 4H₂O. Each aldehyde molecule loses two electrons in becoming the acid.

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