WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Enthalpy Changes for Solids and Solutions
Dissolving: lattice breaking against hydration
- 3 things to know
- A2 Unit 3
Overview
Seventeen recall questions on dissolving: lattice breaking against hydration.
What you need to know
Answer each one before you reveal it.
Why does the hydration term for a salt of formula MX₂ contain three contributions rather than two?
Why does the temperature of the water fall when a salt with a positive enthalpy change of solution dissolves in it?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe the two energy changes that occur when an ionic solid dissolves in water.
Model answer
First the lattice is broken apart into separate gaseous ions, which requires energy and is endothermic. Then each of those ions is hydrated by water molecules, which releases energy and is exothermic.
- 2
How is the enthalpy change of solution related to the lattice breaking enthalpy and the hydration enthalpies?
Model answer
The enthalpy change of solution is the lattice breaking enthalpy plus the sum of the hydration enthalpies of all the ions produced by one formula unit.
- 3
Using lattice breaking enthalpy of sodium chloride +787, hydration enthalpy of the sodium ion −406 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of sodium chloride.
Model answer
The enthalpy change of solution is 787 + (−406) + (−364) = 787 - 770 = +17 kJ mol⁻¹. The dissolving is therefore slightly endothermic.
- 4
Using lattice breaking enthalpy of potassium chloride +711, hydration enthalpy of the potassium ion −322 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of potassium chloride.
Model answer
The enthalpy change of solution is 711 - 322 - 364 = +25 kJ mol⁻¹.
- 5
Using lattice breaking enthalpy of magnesium chloride +2524, hydration enthalpy of the magnesium ion −1920 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of magnesium chloride.
Model answer
Two moles of chloride ions are hydrated per formula unit, contributing 2 × (−364) = −728 kJ mol⁻¹. The enthalpy change of solution is 2524 - 1920 - 728 = −124 kJ mol⁻¹, so the dissolving is exothermic.
- 6
Using lattice breaking enthalpy of silver chloride +905, hydration enthalpy of the silver ion −464 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of silver chloride and comment on the result.
Model answer
The enthalpy change of solution is 905 - 464 - 364 = +77 kJ mol⁻¹. This is strongly endothermic, since the lattice is very difficult to break and the hydration energy released falls a long way short of repaying it, which is consistent with silver chloride being very sparingly soluble.
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