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Enthalpy Changes for Solids and Solutions

Dissolving: lattice breaking against hydration

  • 3 things to know
  • A2 Unit 3

Overview

Seventeen recall questions on dissolving: lattice breaking against hydration.

What you need to know

Answer each one before you reveal it.

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Key term

Describe the two energy changes that occur when an ionic solid dissolves in water.

Key term

Why does the hydration term for a salt of formula MX₂ contain three contributions rather than two?

Key term

Why does the temperature of the water fall when a salt with a positive enthalpy change of solution dissolves in it?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the two energy changes that occur when an ionic solid dissolves in water.

    Model answer

    First the lattice is broken apart into separate gaseous ions, which requires energy and is endothermic. Then each of those ions is hydrated by water molecules, which releases energy and is exothermic.

  2. 2

    How is the enthalpy change of solution related to the lattice breaking enthalpy and the hydration enthalpies?

    Model answer

    The enthalpy change of solution is the lattice breaking enthalpy plus the sum of the hydration enthalpies of all the ions produced by one formula unit.

  3. 3

    Using lattice breaking enthalpy of sodium chloride +787, hydration enthalpy of the sodium ion −406 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of sodium chloride.

    Model answer

    The enthalpy change of solution is 787 + (−406) + (−364) = 787 - 770 = +17 kJ mol⁻¹. The dissolving is therefore slightly endothermic.

  4. 4

    Using lattice breaking enthalpy of potassium chloride +711, hydration enthalpy of the potassium ion −322 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of potassium chloride.

    Model answer

    The enthalpy change of solution is 711 - 322 - 364 = +25 kJ mol⁻¹.

  5. 5

    Using lattice breaking enthalpy of magnesium chloride +2524, hydration enthalpy of the magnesium ion −1920 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of magnesium chloride.

    Model answer

    Two moles of chloride ions are hydrated per formula unit, contributing 2 × (−364) = −728 kJ mol⁻¹. The enthalpy change of solution is 2524 - 1920 - 728 = −124 kJ mol⁻¹, so the dissolving is exothermic.

  6. 6

    Using lattice breaking enthalpy of silver chloride +905, hydration enthalpy of the silver ion −464 and hydration enthalpy of the chloride ion −364 kJ mol⁻¹, calculate the enthalpy change of solution of silver chloride and comment on the result.

    Model answer

    The enthalpy change of solution is 905 - 464 - 364 = +77 kJ mol⁻¹. This is strongly endothermic, since the lattice is very difficult to break and the hydration energy released falls a long way short of repaying it, which is consistent with silver chloride being very sparingly soluble.

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