WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Halogenoalkanes
Uses of halogenoalkanes, CFCs and the ozone layer: radical mechanism
- 3 things to know
- AS Unit 2
Overview
Eight recall questions on uses of halogenoalkanes, CFCs and the ozone layer: radical mechanism.
What you need to know
Answer each one before you reveal it.
Write an equation for the initial breakdown of CCl₂F₂ by ultraviolet radiation and state the type of bond fission.
Why is the presence of C–H bonds in a halogenoalkane an advantage from an environmental point of view?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Write an equation for the initial breakdown of CCl₂F₂ by ultraviolet radiation and state the type of bond fission.
Model answer
The equation is CCl₂F₂ → •CClF₂ + Cl•, and the bond fission is homolytic, since each fragment leaves with one of the two shared electrons and both are radicals.
- 2
Write the two equations that show how a chlorine radical destroys ozone, and give the overall equation.
Model answer
The steps are Cl• + O₃ → ClO• + O₂ and ClO• + O₃ → Cl• + 2O₂, and adding them gives the overall equation 2O₃ → 3O₂, since the chlorine radical and the ClO• radical both cancel.
- 3
Why is a chlorine radical described as a catalyst for the destruction of ozone?
Model answer
It is used up in the first step but regenerated unchanged in the second, so it is not consumed overall and a single chlorine radical can go round the cycle many thousands of times, destroying an enormous number of ozone molecules.
- 4
Which species in the ozone-destroying cycle is the intermediate rather than the catalyst?
Model answer
The ClO• radical is the intermediate, because it is made in the first step and used up in the second and does not appear in the overall equation, whereas the chlorine radical is present at the start and at the end.
- 5
Why does a small quantity of CFC released at ground level have such a large effect?
Model answer
The molecule survives long enough to reach the stratosphere, and once there each chlorine atom it carries is released as a radical that acts catalytically, so the number of ozone molecules destroyed is far greater than the number of CFC molecules released.
- 6
Why is the presence of C–H bonds in a halogenoalkane an advantage from an environmental point of view?
Model answer
Molecules containing C–H bonds are attacked by hydroxyl radicals and broken down in the lower atmosphere within a few years, so most of the compound is destroyed long before it can drift up into the stratosphere and release chlorine there.
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