WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Formulae and Equations
Assigning oxidation numbers
- 3 things to know
- AS Unit 1
Overview
Twelve recall questions on Assigning oxidation numbers.
What you need to know
Answer each one before you reveal it.
What is the oxidation number of manganese in the manganate(VII) ion, MnO₄⁻?
What is the oxidation number of sulfur in sulfuric acid?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What rules let you assign oxidation numbers to the atoms in a compound?
Model answer
An uncombined element is zero; a simple ion has an oxidation number equal to its charge; in compounds hydrogen is usually +1 and oxygen usually −2; fluorine is always −1. The oxidation numbers in a neutral compound sum to zero, and in an ion they sum to the charge on the ion.
- 2
What is the oxidation number of manganese in the manganate(VII) ion, MnO₄⁻?
Model answer
Each oxygen is −2, giving 4 × (−2) = −8. The total must equal the ionic charge of −1, so the manganese is +7, since +7 − 8 = −1. The Roman numeral in the name states this value directly.
- 3
Work out the oxidation number of chromium in Cr₂O₇²⁻.
Model answer
The seven oxygens contribute 7 × (−2) = −14. For the total to be −2 the two chromium atoms must supply +12, so each chromium is +6.
- 4
What is the oxidation number of sulfur in sulfuric acid?
Model answer
In H₂SO₄ the two hydrogens give +2 and the four oxygens give −8, a running total of −6. The molecule is neutral, so the sulfur must be +6.
- 5
Deduce the oxidation number of nitrogen in the ammonium ion and in the nitrate ion.
Model answer
In NH₄⁺ the four hydrogens give +4 and the total is +1, so nitrogen is −3. In NO₃⁻ the three oxygens give −6 and the total is −1, so nitrogen is +5.
- 6
Hydrogen is usually +1, but what is its oxidation number in sodium hydride, NaH?
Model answer
It is −1. Sodium is a metal and always +1 here, so hydrogen must be −1 for the compound to be neutral. Hydrogen takes −1 whenever it is bonded to a less electronegative metal.
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