WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Formulae and Equations
Using oxidation numbers to follow redox changes
- 3 things to know
- AS Unit 1
Overview
Nine recall questions on using oxidation numbers to follow redox changes.
What you need to know
Answer each one before you reveal it.
In the reaction Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), identify what is oxidised and what is reduced.
In the disproportionation Cl₂ + 2NaOH → NaCl + NaClO + H₂O, show using oxidation numbers why chlorine is described as both oxidised and reduced.
Questions from this subtopic
Each one with the model answer underneath.
- 1
How do oxidation numbers tell you whether a species has been oxidised or reduced?
Model answer
Oxidation is an increase in oxidation number, because it corresponds to a loss of electrons. Reduction is a decrease in oxidation number, corresponding to a gain of electrons.
- 2
In the reaction Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), identify what is oxidised and what is reduced.
Model answer
Zinc goes from 0 to +2, an increase, so it is oxidised. Copper goes from +2 to 0, a decrease, so it is reduced. The zinc is therefore the reducing agent and the copper(II) ion the oxidising agent.
- 3
Why is the reaction of magnesium with oxygen classed as redox even though no ions appear on the left-hand side?
Model answer
In 2Mg(s) + O₂(g) → 2MgO(s) magnesium rises from 0 to +2 and oxygen falls from 0 to −2. Both oxidation numbers change, so electrons have been transferred and the reaction is redox.
- 4
A reagent is described as an oxidising agent. What happens to its own oxidation number during the reaction?
Model answer
It falls. An oxidising agent takes electrons from something else, so it is itself reduced and its oxidation number decreases.
- 5
Is the reaction between hydrochloric acid and sodium hydroxide a redox reaction? Explain your answer using oxidation numbers.
Model answer
No. Hydrogen stays at +1, oxygen at −2, chlorine at −1 and sodium at +1 throughout, so no oxidation number changes. It is a neutralisation, involving transfer of a proton rather than of electrons.
- 6
What does the Roman numeral in a name such as potassium manganate(VII) actually tell you?
Model answer
It gives the oxidation number of the named element in that species, so the manganese in MnO₄⁻ is at +7. It is a statement about oxidation number, not about the charge on the ion, which is −1.
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