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Formulae and Equations

Using oxidation numbers to follow redox changes

  • 3 things to know
  • AS Unit 1

Overview

Nine recall questions on using oxidation numbers to follow redox changes.

What you need to know

Answer each one before you reveal it.

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Numbers

How do oxidation numbers tell you whether a species has been oxidised or reduced?

Key term

In the reaction Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), identify what is oxidised and what is reduced.

Key term

In the disproportionation Cl₂ + 2NaOH → NaCl + NaClO + H₂O, show using oxidation numbers why chlorine is described as both oxidised and reduced.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    How do oxidation numbers tell you whether a species has been oxidised or reduced?

    Model answer

    Oxidation is an increase in oxidation number, because it corresponds to a loss of electrons. Reduction is a decrease in oxidation number, corresponding to a gain of electrons.

  2. 2

    In the reaction Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), identify what is oxidised and what is reduced.

    Model answer

    Zinc goes from 0 to +2, an increase, so it is oxidised. Copper goes from +2 to 0, a decrease, so it is reduced. The zinc is therefore the reducing agent and the copper(II) ion the oxidising agent.

  3. 3

    Why is the reaction of magnesium with oxygen classed as redox even though no ions appear on the left-hand side?

    Model answer

    In 2Mg(s) + O₂(g) → 2MgO(s) magnesium rises from 0 to +2 and oxygen falls from 0 to −2. Both oxidation numbers change, so electrons have been transferred and the reaction is redox.

  4. 4

    A reagent is described as an oxidising agent. What happens to its own oxidation number during the reaction?

    Model answer

    It falls. An oxidising agent takes electrons from something else, so it is itself reduced and its oxidation number decreases.

  5. 5

    Is the reaction between hydrochloric acid and sodium hydroxide a redox reaction? Explain your answer using oxidation numbers.

    Model answer

    No. Hydrogen stays at +1, oxygen at −2, chlorine at −1 and sodium at +1 throughout, so no oxidation number changes. It is a neutralisation, involving transfer of a proton rather than of electrons.

  6. 6

    What does the Roman numeral in a name such as potassium manganate(VII) actually tell you?

    Model answer

    It gives the oxidation number of the named element in that species, so the manganese in MnO₄⁻ is at +7. It is a statement about oxidation number, not about the charge on the ion, which is −1.

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