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Chemistry of the P-Block

Group 4 oxides and chlorides, and lead in solution: chloride hydrolysis and lead(II) precipitates

  • 3 things to know
  • A2 Unit 3

Overview

Why SiCl₄ hydrolyses but CCl₄ does not, and the precipitates lead(II) ions form with sodium hydroxide, dilute hydrochloric acid and potassium iodide, including what happens with excess reagent.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

Both CCl₄ and SiCl₄ are liquids of similar structure. Why can the difference in their reactions with water not be explained by bond polarity alone?

Process

Why is silicon tetrachloride, with a boiling temperature of 58 °C, so much more volatile than lead(II) chloride, which melts at about 500 °C?

Key term

Explain why tetrachloromethane can be used as a solvent for non-polar substances while lead(II) chloride cannot dissolve in it.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Both CCl₄ and SiCl₄ are liquids of similar structure. Why can the difference in their reactions with water not be explained by bond polarity alone?

    Model answer

    The Si–Cl bond is more polar than the C–Cl bond, but the C–Cl bond is also polar enough to be attacked in principle. The real difference is that carbon has no route to a low-energy intermediate because it cannot expand its octet, so the reaction is blocked kinetically rather than by lack of polarity.

  2. 2

    Why is silicon tetrachloride, with a boiling temperature of 58 °C, so much more volatile than lead(II) chloride, which melts at about 500 °C?

    Model answer

    Silicon tetrachloride consists of discrete non-polar molecules held together only by weak van der Waals forces, which are easily overcome. Lead(II) chloride is a giant ionic lattice, so a great deal of energy is needed to separate the oppositely charged ions.

  3. 3

    Explain why tetrachloromethane can be used as a solvent for non-polar substances while lead(II) chloride cannot dissolve in it.

    Model answer

    Tetrachloromethane is a non-polar molecular liquid, so it mixes with substances whose intermolecular forces are also weak van der Waals forces. Lead(II) chloride is ionic, and the weak forces from a non-polar solvent cannot supply the energy needed to break up its ionic lattice.

  4. 4

    Sodium hydroxide solution is added drop by drop, and then in excess, to a solution of lead(II) nitrate. Give the observations and the equations.

    Model answer

    A white precipitate of lead(II) hydroxide forms: Pb²⁺(aq) + 2OH⁻(aq) → Pb(OH)₂(s). Adding excess alkali dissolves the precipitate to give a colourless solution of the plumbate(II) ion: Pb(OH)₂(s) + 2OH⁻(aq) → [Pb(OH)₄]²⁻(aq).

  5. 5

    Why does the white precipitate obtained from lead(II) ions and sodium hydroxide dissolve when more alkali is added?

    Model answer

    Lead(II) hydroxide is amphoteric. In excess hydroxide it behaves as an acid, accepting two further hydroxide ions to form the soluble tetrahydroxoplumbate(II) ion, so the solid dissolves and a colourless solution remains.

  6. 6

    Dilute hydrochloric acid is added to lead(II) nitrate solution. State what is seen and write the ionic equation.

    Model answer

    A white precipitate of lead(II) chloride forms immediately: Pb²⁺(aq) + 2Cl⁻(aq) → PbCl₂(s).

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