WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemistry of the P-Block
Chlorine, chlorate and the sodium halides: bleaching and bactericidal action of Cl2
- 3 things to know
- A2 Unit 3
Overview
Recall questions on bleaching action of Cl2 and bactericidal action of Cl2.
What you need to know
Answer each one before you reveal it.
Why does bleach lose its strength if the bottle is left open or stored in a warm place?
Explain why chlorate(I) is used to bleach paper pulp rather than a coloured pigment being simply washed out.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Explain how sodium chlorate(I) bleaches a coloured dye.
Model answer
The chlorate(I) ion is a powerful oxidising agent. It oxidises the dye molecule, breaking up the extended system of delocalised electrons that is responsible for absorbing visible light. Once that conjugated system is destroyed the molecule no longer absorbs in the visible region and the material appears white.
- 2
Why is a bleaching action always an oxidation when chlorine-based bleaches are used?
Model answer
The bleach works by removing electrons from the coloured molecule. Chlorine and chlorate(I) are strong oxidising agents and take those electrons, so the dye is oxidised while the chlorine species is reduced, usually to chloride ions.
- 3
Write a half-equation showing the chlorate(I) ion acting as an oxidising agent in acidic solution.
Model answer
ClO⁻ + 2H⁺ + 2e⁻ → Cl⁻ + H₂O. Chlorine is reduced from +1 to −1 as the ion gains two electrons from whatever it oxidises.
- 4
Give the half-equation for chlorine acting as an oxidising agent, and state its standard electrode potential.
Model answer
Cl₂ + 2e⁻ → 2Cl⁻, with a standard electrode potential of +1.36 V. The large positive value shows that chlorine has a strong tendency to gain electrons and so is a powerful oxidising agent.
- 5
Chlorine is added to drinking water. Explain how this kills bacteria.
Model answer
The chloric(I) acid and chlorate(I) ions formed are strong oxidising agents. They oxidise proteins and enzymes in the bacterial cell, and damage the cell membrane, so the essential chemistry of the cell can no longer function and the bacterium dies.
- 6
Which species is mainly responsible for the disinfecting action of chlorinated water, and why is pH important?
Model answer
Chloric(I) acid, HClO, is the main disinfectant, and it is a more effective bactericide than the chlorate(I) ion. Since HClO is a weak acid it is largely undissociated in slightly acidic conditions but converted to ClO⁻ in alkaline conditions, so keeping the pH slightly acidic keeps the disinfection efficient.
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