WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Chemical Calculations
Yield, atom economy and experimental uncertainty: concepts of atom economy and percentage yield
- 3 things to know
- AS Unit 1
Overview
Recall questions on concepts of atom economy and percentage yield.
What you need to know
Answer each one before you reveal it.
4.86 g of magnesium is burned in oxygen and 7.42 g of magnesium oxide is collected. Calculate the percentage yield.
28.0 g of nitrogen reacts with excess hydrogen and 8.50 g of ammonia is isolated. What is the percentage yield?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is percentage yield, and how is it calculated?
Model answer
It compares how much product was actually obtained with the maximum the equation predicts. Percentage yield = (actual yield ÷ theoretical yield) × 100, using either masses or amounts in moles, provided the same measure is used for both.
- 2
Why is the percentage yield of a reaction usually less than 100%?
Model answer
Some product is lost during transfer, filtration and purification; the reaction may not go to completion, especially if it reaches equilibrium; and side reactions may convert some of the reactants into other products.
- 3
Why can a percentage yield never legitimately exceed 100%?
Model answer
The theoretical yield is the most the reactants can possibly give, since atoms cannot be created. A figure above 100% means the product was impure or still wet, or that a measurement was wrong.
- 4
4.86 g of magnesium is burned in oxygen and 7.42 g of magnesium oxide is collected. Calculate the percentage yield.
Model answer
The equation is 2Mg + O₂ → 2MgO. n(Mg) = 4.86 ÷ 24.3 = 0.200 mol, so n(MgO) = 0.200 mol and the theoretical mass is 0.200 × 40.3 = 8.06 g. The percentage yield is (7.42 ÷ 8.06) × 100 = 92.1%.
- 5
28.0 g of nitrogen reacts with excess hydrogen and 8.50 g of ammonia is isolated. What is the percentage yield?
Model answer
The equation is N₂ + 3H₂ → 2NH₃. n(N₂) = 28.0 ÷ 28.0 = 1.00 mol, so the theoretical amount of ammonia is 2.00 mol, a mass of 2.00 × 17.0 = 34.0 g. The percentage yield is (8.50 ÷ 34.0) × 100 = 25.0%.
- 6
What is atom economy, and what does it measure that percentage yield does not?
Model answer
Atom economy is the proportion of the mass of the reactants that ends up in the desired product, calculated from the balanced equation as (mass of desired product ÷ total mass of all products) × 100. It measures how wasteful the chosen reaction is in principle, whereas percentage yield measures how well that reaction was carried out in practice.
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