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Chemical Calculations

Yield, atom economy and experimental uncertainty: concepts of atom economy and percentage yield

  • 3 things to know
  • AS Unit 1

Overview

Recall questions on concepts of atom economy and percentage yield.

What you need to know

Answer each one before you reveal it.

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Key term

Why is the percentage yield of a reaction usually less than 100%?

Numbers

4.86 g of magnesium is burned in oxygen and 7.42 g of magnesium oxide is collected. Calculate the percentage yield.

Key term

28.0 g of nitrogen reacts with excess hydrogen and 8.50 g of ammonia is isolated. What is the percentage yield?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is percentage yield, and how is it calculated?

    Model answer

    It compares how much product was actually obtained with the maximum the equation predicts. Percentage yield = (actual yield ÷ theoretical yield) × 100, using either masses or amounts in moles, provided the same measure is used for both.

  2. 2

    Why is the percentage yield of a reaction usually less than 100%?

    Model answer

    Some product is lost during transfer, filtration and purification; the reaction may not go to completion, especially if it reaches equilibrium; and side reactions may convert some of the reactants into other products.

  3. 3

    Why can a percentage yield never legitimately exceed 100%?

    Model answer

    The theoretical yield is the most the reactants can possibly give, since atoms cannot be created. A figure above 100% means the product was impure or still wet, or that a measurement was wrong.

  4. 4

    4.86 g of magnesium is burned in oxygen and 7.42 g of magnesium oxide is collected. Calculate the percentage yield.

    Model answer

    The equation is 2Mg + O₂ → 2MgO. n(Mg) = 4.86 ÷ 24.3 = 0.200 mol, so n(MgO) = 0.200 mol and the theoretical mass is 0.200 × 40.3 = 8.06 g. The percentage yield is (7.42 ÷ 8.06) × 100 = 92.1%.

  5. 5

    28.0 g of nitrogen reacts with excess hydrogen and 8.50 g of ammonia is isolated. What is the percentage yield?

    Model answer

    The equation is N₂ + 3H₂ → 2NH₃. n(N₂) = 28.0 ÷ 28.0 = 1.00 mol, so the theoretical amount of ammonia is 2.00 mol, a mass of 2.00 × 17.0 = 34.0 g. The percentage yield is (8.50 ÷ 34.0) × 100 = 25.0%.

  6. 6

    What is atom economy, and what does it measure that percentage yield does not?

    Model answer

    Atom economy is the proportion of the mass of the reactants that ends up in the desired product, calculated from the balanced equation as (mass of desired product ÷ total mass of all products) × 100. It measures how wasteful the chosen reaction is in principle, whereas percentage yield measures how well that reaction was carried out in practice.

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