WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Alcohols and Carboxylic Acids
Making an ester and separating it by distillation: yield
- 3 things to know
- AS Unit 2
Overview
Recall questions on difference between simple and fractional distillation.
What you need to know
Answer each one before you reveal it.
Why is the dried ester distilled a second time?
Calculate the relative molecular mass of methyl propanoate, CH₃CH₂COOCH₃. Use A(C) = 12.0, A(H) = 1.0 and A(O) = 16.0.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why is the dried ester distilled a second time?
Model answer
The final distillation separates the ester from any remaining higher-boiling or lower-boiling impurities. Only the fraction distilling at the known boiling temperature of the ester is collected, which gives a pure product.
- 2
What is the difference between simple and fractional distillation?
Model answer
Simple distillation uses a still head alone and separates liquids whose boiling temperatures differ widely. Fractional distillation adds a packed column between the flask and the still head, on which the vapour repeatedly condenses and re-evaporates, and each cycle enriches the vapour in the more volatile component, so liquids with close boiling temperatures can be separated.
- 3
12.0 g of ethanoic acid is heated under reflux with an excess of ethanol and 13.2 g of ethyl ethanoate is obtained. Calculate the percentage yield. Use M(CH₃COOH) = 60.0 g mol⁻¹ and M(CH₃COOC₂H₅) = 88.0 g mol⁻¹.
Model answer
n(CH₃COOH) = 12.0 / 60.0 = 0.200 mol. The acid is the limiting reactant and reacts in a 1 : 1 ratio, so the theoretical yield of ester is 0.200 × 88.0 = 17.6 g. Percentage yield = (13.2 / 17.6) × 100 = 75.0%.
- 4
Calculate the relative molecular mass of methyl propanoate, CH₃CH₂COOCH₃. Use A(C) = 12.0, A(H) = 1.0 and A(O) = 16.0.
Model answer
The molecular formula is C₄H₈O₂. Mr = (4 × 12.0) + (8 × 1.0) + (2 × 16.0) = 48.0 + 8.0 + 32.0 = 88.0.
- 5
Draw out, in words, the arrangement of atoms in the ester link.
Model answer
A carbon atom is joined to an oxygen atom by a double bond and to a second oxygen atom by a single bond, and that second oxygen is joined to the carbon of an alkyl group, giving –C(=O)–O–C–.
- 6
Explain why the water formed in esterification contains the oxygen atom that came from the carboxylic acid rather than from the alcohol.
Model answer
The alcohol attacks the carbonyl carbon through the oxygen of its hydroxyl group, so that oxygen ends up in the ester link. The hydroxyl group originally on the acid carbon is the one that leaves, taking a hydrogen ion with it to form the water molecule.
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