WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
Stereoisomerism
E‒Z isomerism and the priority rules
- 3 things to know
- A2 Unit 4
Overview
Recall questions on E‒Z isomerism and the priority rules.
What you need to know
Answer each one before you reveal it.
Why is there no equivalent isomerism about a carbon-to-carbon single bond?
Explain why propene and 1,1-dichloroethene show no E–Z isomerism, and why there is no such isomerism about a single bond.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why does a carbon-to-carbon double bond give rise to stereoisomerism?
Model answer
The double bond consists of a sigma bond and a pi bond, and the pi bond is formed by sideways overlap of p orbitals above and below the plane. Twisting about the bond axis would break that overlap, so rotation is restricted and the groups on each carbon are locked on one side or the other.
- 2
Why is there no equivalent isomerism about a carbon-to-carbon single bond?
Model answer
A single bond is a sigma bond with its electron density along the axis joining the nuclei, so rotation about it does not disturb the overlap. The groups can spin freely at room temperature and any two arrangements are simply the same molecule seen at different moments.
- 3
State the condition a double bond must satisfy for E‒Z isomerism to be possible.
Model answer
Each of the two carbon atoms of the C=C must carry two different atoms or groups. If either carbon carries two identical groups, swapping them gives the same molecule and no isomerism arises.
- 4
Does propene show E‒Z isomerism?
Model answer
No. In CH₂=CHCH₃ the terminal carbon carries two hydrogen atoms, which are identical, so there is only one possible arrangement in space.
- 5
Does 1,1-dichloroethene show E‒Z isomerism, and does 1,2-dichloroethene?
Model answer
1,1-Dichloroethene does not, because one carbon carries two chlorines and the other carries two hydrogens, so each carbon has a duplicated group. 1,2-Dichloroethene does, because each carbon carries one hydrogen and one chlorine, which can be arranged on the same side or on opposite sides.
- 6
State the rule used to assign priority to the groups on each carbon of a double bond.
Model answer
On each carbon separately, compare the atomic numbers of the two atoms directly attached to it; the atom of higher atomic number takes priority. If those two atoms are the same element, move outwards along each branch and compare the sets of atoms attached to them, again by atomic number, until a difference is found.
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