WJEC A-Level Chemistry 1410QS
Formulae and Equations
Basic Ideas About Atoms
Chemical Calculations
Bonding
Solid Structures
The Periodic Table
Simple Equilibria and Acid-Base Reactions
Thermochemistry
Rates of Reaction
The Wider Impact of Chemistry
Organic Compounds
Hydrocarbons
Halogenoalkanes
Alcohols and Carboxylic Acids
Instrumental Analysis
Redox and Standard Electrode Potential
Redox Reactions
Chemistry of the P-Block
Chemistry of the D-Block Transition Metals
Chemical Kinetics
Enthalpy Changes for Solids and Solutions
Entropy and Feasibility of Reactions
Equilibrium Constants
Acid-Base Equilibria
Stereoisomerism
Aromaticity
Alcohols and Phenols
Aldehydes and Ketones
Carboxylic Acids and Their Derivatives
Amines
Amino Acids, Peptides and Proteins
Organic Synthesis and Analysis
Practical Skills and Techniques
Planning, Analysis and Evaluation
Core Experiments and Their Chemistry
Mathematical Skills in Chemistry
The Periodic Table
Group 7: the halogens — halide ions as reducing agents, uses of chlorine and the chlorate equilibrium
- 3 things to know
- AS Unit 1
Overview
Recall questions on the halogens — halide ions as reducing agents, uses of chlorine and the chlorate equilibrium.
What you need to know
Answer each one before you reveal it.
Write the equation for the reaction of chlorine with aqueous sodium bromide and describe what is seen.
Explain, using oxidation numbers, why the reaction between chlorine and bromide ions is a redox reaction.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Chlorine and bromine both oxidise Fe²⁺ to Fe³⁺, but iodine does not. Explain, using electrode potentials.
Model answer
The Fe³⁺ to Fe²⁺ system has a standard electrode potential of +0.77 V. Chlorine at +1.36 V and bromine at +1.07 V are both more positive, so they can take an electron from Fe²⁺ and oxidise it. Iodine at +0.54 V is less positive, so it cannot, and in fact iodide ions reduce Fe³⁺ to Fe²⁺ instead.
- 2
Write the equation for the reaction of chlorine with aqueous sodium bromide and describe what is seen.
Model answer
Cl₂ + 2NaBr → 2NaCl + Br₂. The colourless sodium bromide solution turns orange or yellow-brown as bromine is displaced. The ionic equation is Cl₂ + 2Br⁻ → 2Cl⁻ + Br₂.
- 3
Write the equation for the reaction between chlorine and aqueous potassium iodide, and describe the observations.
Model answer
Cl₂ + 2KI → 2KCl + I₂. The solution turns brown as iodine is displaced, and with more concentrated solutions a grey-black solid of iodine is deposited. Shaking with hexane gives a violet upper layer, and adding starch solution gives a blue-black colour.
- 4
Give the ionic equation for the reaction of bromine with potassium iodide solution and state the colour change.
Model answer
Br₂ + 2I⁻ → 2Br⁻ + I₂. The pale orange bromine water darkens to the brown of iodine solution, and a hexane layer shaken with the mixture turns violet.
- 5
Explain, using oxidation numbers, why the reaction between chlorine and bromide ions is a redox reaction.
Model answer
Chlorine falls from 0 in Cl₂ to −1 in Cl⁻, so it gains electrons and is reduced, making it the oxidising agent. Bromine rises from −1 in Br⁻ to 0 in Br₂, so it loses electrons and is oxidised, making bromide the reducing agent. Electrons pass from bromide ions to chlorine molecules.
- 6
Why does no reaction occur when bromine water is added to potassium chloride solution?
Model answer
Bromine is a weaker oxidising agent than chlorine, so it cannot take electrons from chloride ions. The chloride ion is smaller and holds its outer electrons more tightly than bromide does, so it is not oxidised and the solution simply stays the colour of the added bromine.
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